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233_Problem CHAPTER 9

# 233_Problem CHAPTER 9 - PROBLEM 9.162 CONTINUED Then I uv =...

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PROBLEM 9.162 CONTINUED Then 3 2 0 sin cos uv uv I dI m a d π θ θ θ = = 2 3 2 3 0 1 1 sin 2 2 m a m a π θ = = Thus, ( ) 3 1 1 1 2 yz I m R = and ( ) ( ) 3 3 2 1 3 5 1 1 2 2 zx xy I m R I m R = − = − Because of 90 ° rotations of the coordinate axes. Finally, ( ) ( ) ( ) ( ) 1 1 1 3 3 3 1 3 5 xy xy x y x y xy I I I m x y I m x y I ′ ′ ′ ′ = Σ = + + + + or 3 1 1 2 xy I m R = − W ( ) ( ) ( ) ( ) 3 3 3 5 5 5 1 3 5 yz yz yz y z y z I I I I m y z I m y z ′ ′ ′ ′
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