236_Problem CHAPTER 9

236_Problem CHAPTER 9 - PROBLEM 9.164 CONTINUED (b) Because...

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PROBLEM 9.164 CONTINUED ( b ) Because of the symmetry of the body, xy I and yz I can be deduced by considering the circular permutation of ( ) ,, xyz and ( ) abc . Thus 1 20 xy I mab = W 1 20 yz I mbc = W Alternative solution for part a First divide the tetrahedron into a series of thin horizontal slices of thickness dy as shown. Now 1 ay xy a a bb  =− + =   and 1 cy zy c c The mass dm of the slab is 2 11 1 22 y dm dV xzdy ac dy b ρρ ρ == = Now , Area zx zx dI tdI = where td y = and , Area 1 24 zx dI x z = from the results of Sample Problem 9.6 Then () 2 2 1 24 yy dIzx dy a c  
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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