269_Problem CHAPTER 9

269_Problem CHAPTER 9 - PROBLEM 9.182 CONTINUED Then ( ) 2...

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PROBLEM 9.182 CONTINUED Then () () () 2 2 2 22 0.05985 1 xx z λλ λ  + +=  ( ) 2 0.99821 x = ( ) 2 0.05974 y = and ( ) ( ) ( ) 2 2 2 3.43 , 86.6 , 90.0 xyz = °= ° θθθ W 3 : K ( ) ( )( ) 3 3 3 0 xy x y y II K +− = ( )( ) 3 3 0 zz IK = Now ( ) 3 3 0 ⇒= Substituting () ( ) 33 3 3 3 0.96211 10 50.125 10 50.1824 10 0 xy −− −× + × × = ( ) ( ) 3 3 0.96211 10 0.0574 10 0 ×− ×= or ( ) ( ) 3 3 16.7615 yx =− Have 2 2 2 3 16.7615 1 z + −+ = yields ( ) ( ) 3 3 0.059555 and 0.998231
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This note was uploaded on 07/11/2011 for the course EGM 2511 taught by Professor Jenkins during the Spring '08 term at University of Florida.

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