insideEoQεΦ==RAρ)]TT(1[RRoo-α+==RAρ2.mag and directions of electric field ½ btwn the 2 charges. (1/2 way btwn is 2m) Add once they point in the same direction. Direction of E. Field is in the negative x direction, because the point charge is + and therefore repulsed by the +7nC charge and attracted to the -5nC charge. If they were the same sign they would subtract as the vectors are pointed in the opposite direction.3.Gauss’ Law states that the electric flux through any closed surface is equal to the net charge Q inside the surface divided by εo(can be used to calculate ELECTRIC FIELDS)EA =(Permittivity - material's ability to transmit electric field)What is the ELECTRIC FLUXthrough the surface?4. If a battery is connected to parallel plates what is the magnitude of the electric field between the plates.V =-ExΔΔE= V/x ∆5.A charge of is at the origin and a charge of is at the point - Find the electric potential at?
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