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quiz 2B sol - Solutions to Quiz 2B www.math.u.edu/harringt...

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Solutions to Quiz 2B www.math.ufl.edu/˜harringt September 8, 2007 1. Factor Completely. (a) x 2 + 7 x + 5 Here we will use the AC -Method. The AC = 5 * 1 = 5. However, there are no two numbers a, b such that a + b = 7 and ab = 5. Hence, the polynomial is prime. (b) 2 x 2 + 7 xy - 4 y 2 AC -Method: Here AC = - 4 * 2 = - 8. Futhermore, AC = - 8 = 8 * ( - 1) and 8 - 1 = 7 (The middle term.) Thus, 2 x 2 + 7
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