Unformatted text preview: 3)( x 22 x + 1) Solution: (2 x3)( x 22 x + 1) = 2 x 34 x 2 + 2 x3 x 2 + 6 x3 = 2 x 37 x 2 + 8 x3 3. (1pt) Evaluate ±1 64 ²1 / 3 Solution: ±1 64 ²1 / 3 = (64) 1 / 3 = 3 √64 =3 √ 4 3 =4 1...
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 Fall '08
 WILLIAMSON
 Calculus, Algebra, 2pts, 1pt, Jason Harrington

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