{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Screen shot 2011-06-22 at 12.04.16 AM

# Screen shot 2011-06-22 at 12.04.16 AM - Determine...

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Determine theepeedent'thetnn memes Be they pans mehnther. Trentthepullej'ea a. uniﬁm'm disk. The eeneleratien nt' gravity is 9.3 mfez- ﬁtment m 1.5462? mfa. Explenntlnn: Let: M=ekg. 3:41:53], mt=351i51 me:l?'hg, and .FI.=2In- Frem museum-inn diam-g}- KI+K3+KM=—ﬂ.ﬂ i 13': 2 mm me Mu .Fl. 2 + e + .1 ‘Em—mug t2m1+2ma+MJ u” =2tm: —mﬂyh, h whenei lethe height- Tehingnn elippjngintn anmunt 1 u: Efﬁe —m:]'trh Hm: +1112] +M _ em kg — 17 kg] {9.3 mini] ‘1/ 2{eskg+neg]J—3Itg tut-Jim =|1.ﬂdE-21'm,."e|. ieynnrde: {I11 1|].ﬂpninte Aunifnemrndnflenghﬂdmandmmﬂﬁjkg it: free to rotate about a [rtetlnnlem pit-at at nneendineeertleelplene,ﬂintheﬂgnre. 'I'hemd'tereleaeedﬁnmreetin thehnt-imntel WET, ia- the magnitude hi the initial angular amelernthn at" the red? The aeederathn nt' grewity is 11.3 malteda . Emmet emu-er: 0.13125 lﬂlil'IE-a- Explanation: Let: L=2dm and M=Eﬁjig. The Hnematim equeﬂnna mnnnt he need fnrnntneinne theyerenntennetantin thin aituettnn. The uni}: [ewe nentﬂhnting tn tnrqne ehnut an exit through the nit-vet ie the ﬂame nt' gravity- Mg alerted en the Elli. an the megnltnde cf the tnrque due tn the rnd‘e weight ehnutanmdethmughthepimtie Mgr. =—= I 1' 3 Cl Mgt l 1 = MI.- 2 3 '3' _3 Erin-ﬂee? _2L_2 Edtn = 9.5125 maﬁa? - : {I12 [part 1 nfﬂ] 1|].D pnintn Fen: pet-tidee Iwith mm 5 kg, 7' kg, 3 kg, ﬂ' ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online