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Unformatted text preview: P(V)=0.65 P(V c )=0.35 P(I |V)=0.8 P(I c | V)=0.2 P(I c | V c )=0.9 P(I |V c )=0.1 To find the probability that you have a virus given that one of your programs says your are infected, I used Bayes’ rule: You want at least 9 of the 12 programs to agree, so this is a binomial distribution where I ≥ 9: An example calculation, where I = 9: So the total probability is:...
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- Conditional Probability, Probability theory, Binomial distribution, wrong decision