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Unformatted text preview: PHYSICS TEST 2 STUDY GUIDE: CHAPTER 5: NEWTONS LAWS (Equilibrium, Free Body Diagram) Q1: The force up will be T 2 and the force left will beT 1 . For the diagonal tension, you want to break it up into its x and ycomponents. The force right will be 100cos30 and the force down will be100sin30 and mg. We are going to say mg = 0 because it is a very light ring. Since the ring is stationary, acceleration will be 0. F x = ma = 0 = 100cos30 - T 1 (it doesnot matter which one you make negative since net force is 0) F y = ma = 0 = 100sin30 - T 2 So T 1 = 100cos30 And T 2 = 100sin30 100*cos30= T 1= 86.6 N 100*sin30= T2=50 N Q2: The forces in the figure are acting on a 7.8 object. Find the value of , the x-component of the object's acceleration. Find the value of , the y-component of the object's acceleration. F = ma F x = ma x WHERE: F x = forces in the x direction m = mass a x = acceleration in the x direction If you look at the figure, there are only two forces in the x direction. The first force is the x component force 4.0 N acting If you look at the figure, there are only two forces in the x direction....
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- Fall '08