midterm - Missi Varner Midterm, #1 Descriptive statistics...

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Missi Varner Midterm, #1 Descriptive statistics {10, 20, 2, 8, 0, 23, 15, 5, 10, 12, 15 } Mean = 10.9 x count 11 95% confidence interval for actual Mean: 6.126 thru 15.69 mean 10.91 sample variance 50.69 Standard Deviation = 7.12 sample standard deviation 7.12 minimum 0 Hi = 23.0 Low = 0.00 maximum 23 range 23 Median = 10.0 population variance 46.08 Average Absolute Deviation from Median = 5.45 population standard deviation 6.79 standard error of the mean 2.15 skewness 0.14 kurtosis -0.56 coefficient of variation (CV) 65.26% 1st quartile 6.50 median 10.00 3rd quartile 15.00 interquartile range 8.50 mode 10.00 low extremes 0 low outliers 0 high outliers 0 high extremes 0 normal curve GOF p-value .6015 chi-square(df=1) 0.27 E 2.75 The following unsorted data shows the number of traffic tickets given each day by Deputy Fife over the last eleven days. Compute the descript prepared to answer several questions about the output:
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O(-0.67) 3 O(+0.00) 3 O(+0.67) 3 O(inf.) 2 Stem and Leaf plot for x stem unit = 10 leaf unit = 1 Frequency Stem Leaf 4 0 0 2 5 8 5 1 0 0 2 5 5 2 2 0 3 11 -4500 -4000 -3500 -3000 -2500 -2000 -1500 -1000 -500 0 500 BoxPlot x
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Data Set: 10, 20, 2, 8, 0, 23, 15, 5, 10, 12, 15 Descriptive Statistics: Minimum: 0 Maximum: 23 Range: 23 Count: 11 Sum: 120 Mean: 10.91 Median: 10 Mode: 10, 15 Standard Deviation: 7.12 Variance: 50.69 Mid Range: 11.5 Quartiles: Quartiles: Q1 --> 3.5 Q2 --> 10 Q3 --> 15 Interquartile Range (IQR): 11.5 Sum of Squares: 506.91 Mean Absolute Deviation: 5.54 Root Mean Square (RMS): 12.85 Std Error of Mean: 2.15 Skewness: 0.12 Kurtosis: 1.97 Coefficient of Variation: 0.65 Frequency: Frequency: Value --> Frequency 0 --> 1 2 --> 1 5 --> 1 8 --> 1 10 --> 2 tive statistics for the following data and be
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12 --> 1 15 --> 2 20 --> 1 23 --> 1
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Missi Varner Midterm, #2 Joint Probability
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