Class Test 1 - Version B - Soln

Class Test 1 - Version B - Soln - UaLIOnJ 33 3 n _h J'l‘n...

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Unformatted text preview: UaLIOnJ 33 3 n _h J'l‘n "\ = (Obiin =7— 6 mmmL Mr; Su‘n9|_ -_; _L_ .J. 3 L__“ at L“ :5 3 > D 3 n -g.‘ A M " A‘hfi ‘L- l.’ k =6 " N” 9. "-1 ramm'm ‘ - ram _L _ _._. _ L N “7.2;: 14—:0 til-an “Jun _Ejan - 1 MO = e + WI '3— 1 l _ ea , _l J . _L -‘ " C 4—4: tie! " - 4L? :3 Co="1.C:=C::_= =--‘ <2=I ‘J- ‘lfiL' A .2 - I ’l K: II, (1 -._ m—d W Wed” W Lo: 45““ 7 4' l 6 J ’— IL ' M (“w {V i b) "' ” m a? 60:) area»? = \x ‘. :2. RBC. . l-‘tl 4— LT canth o‘n‘d' (Drab “I‘d Cm --r “L (A . - _ a a: :4 , =2 :7, 0o: (45);; fin— h a M IL$ :9» {ms Ls L\ p at: e=‘ and?” so POL (aw 319 “Av? {fem N “5'6 , 4th flag ' ' —-._’ I 1 ‘ h Lb K-u\.‘ __ a 'b\d-— ’ “a: l ' (A 5 "'5 g‘ ' 1 " A I. _ " a k; 0 W . s l E- ‘- ‘l I A +— l M > ‘ ‘ L _‘ ‘PPJL‘T (5 Ch .— a CA“! '"D'K‘O (“'1 ("370 ~71 :— I Kc Ear ..o - m. H?) KCfl=o 4n - ' “find -' r Norm U:- —— out” ~1“1 — on, 1 -—oUo-F‘Y+C —o_u.—:‘ (n “'9. . -L T: ‘11—L at) . “I -O\ ’7' =. D 12H “" ==~ 0 on. -- OJOIH-Ea \-0.56'—o.\bt7" \r‘rec) = if CA: —o:2>\ CH0); 0. tom 1: -.. J. ’ 5?*0.% arms. a. :5 “fit \ : o..owz. 03qu l— 0.2.1:” [4r 0:245 ‘ _ ,;_____ r h ‘L E b A_ ooGW_ Dfian] «'030180—023 uCrs 83‘ Jan-('0 re )9 M - k b [AOL-'6’ --\ ( ah *‘Ck' ‘01 (cm! “‘7' “brunt-(chm '- ‘LUA \ -ob-E'( —-o m J = L ; 1—4;?" L-\: = 5%?) 1’ (Jc'ifltk-oflffiwu 2f)! %-0_5 'i:*q1 - L (ft-ll :-. b 105 ‘17 Writ/L1 B: 159 Car—0.53 _ 59L 3C #1336 a: WA Cam—on, 2 0,9,, if %';-——01, M \{Qfl - -—\ 1% L Din—1 Q" %:’"q {—0.93 tax; \U-H: ...\.Lb 3:8). 4.. o A»; .L. -: —! __\ “' Ht “ 03“ M0336 11%: _L A fifiouu (0 fl ‘ 0‘ mm.“ Eh) ‘ \3 to“) 4: Ckl Cn-c +* a («—> ' :2 (CA +— h-t ‘1" --.— g bf * re r f’ a 4 ( a .4 o d ( n“ uh! F5 - ’ - .2. - .. 1:. Lin-O c: 1-- I 4 l - 2}.— t :- l cm a + {Wei '6: M Part C: Digital Filters (25 marks, 25 minutes} .C.1. Consider the following linear difference equations or system transfer functions that represent a digital filter. Match each equation or system transfer function with one of the frequency responses (A, B, C, D, E, F) shown below in Fig. C. Show one or two calculations that justifies your choice. ' [2 marks each] (a) yin]=0-8y[n-1]+0-8x[n]-x[n-1] *5? F550 °L% :- mcrpr Mega glam-HE“! was 0&3? r— on»? (b) y[n] =—0.96y[n —2]+ x[n]+ «Exp: —1.]+ x[n n2] .3 C PM Mari e 5' 62;,er . 7 . (c) y[n]=2x[n_sk] __b b 619—. AIR—ea»? cams =3 ‘35., )Q-QzeA—Js du_,wwb..ha{ k=0 . 1 , f d H =— A— we: oer. Mr W} ( ) (Z) 1+l.31522"+0.8649z'2 '3‘ I ‘ ‘4 1+1/iz"+z'2 _ e Hz =— : c. g ( ) 0 '1—1.31522"+0.8649z—2 ‘3 L PM ’6 "" " 7*1 False-525.3%: A FREE: neseowss: a FREQ sameness: 1’} a. s m "ram assmwse: E '3. ii} FREWEHQ‘F" Em} FREQUEWY {m} Fig. C. Frequency responses shown over the interval —72' < c?) < 72'. ‘ ECSE-304A: Class Test #1 (Version B) 3' is i 2 i! ll 1 5, h ‘4’ I?) f 5 °~T¥an3c9 \nJ-——L3'———7’ '5 I A‘ A “a, pwmw mtg AAA "T “"5, "U‘Ib 0 "r5 “7;, 1T J“: .13qu c .. g -.-. — - L-t—e 3L-\:‘~J - -‘a (l ’ ‘3-“1 63m: \L‘t-oflcé ll ) —fi‘r—————————. A“ :1? —-"'§’\‘( J‘ 3 C ‘3 '3 _. ° ’3 ; t1 .. e5; 3 —-'re. :\ :— 4.) —'2 a ‘ 3 g “E? — 3!:4) ‘u '2»! ut" ~tr C-x— Dfie‘) {2 \Litvo 1): as); D a“ ‘2 —o ‘J ’2 0 7 7' +0 .. L. _ \= @z —_4;' 3 ’ o-q=33 -— \LLU L f( 1405\15’3 ‘L t\ ‘lLJA \fi-DVQFE-L = LQ2-=t+-F\- ’1' L§:\ ...
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Class Test 1 - Version B - Soln - UaLIOnJ 33 3 n _h J'l‘n...

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