MT+1+Key - Biological Sciences 101 Summer Session I 2011...

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Biological Sciences 101 Summer Session I 2011 Midterm I Exam Key [Each answer worth max of 4 pts] 1a. The 18 tall parental plants are homozygous T 1 T 1 for the wild-type tall allele and all the 215 F 1 progeny are T 1 T 1 . 1b. The 22 tall parental plants and their 260 F 1 progeny are all homozygous T 1 T 1 1c. The short plants carry a dominant allele in heterozygous, they are T 1 T 2 . The tall progeny are T 1 T 1 and the short progeny are T 1 T 2 . 1d. The ratio of short to tall is 3:1, confirming that the 10 short plants used in cross III are heterozygous ( T 1 T 2 ). 2a. This is most likely X-linked recessive inheritance. The difference in the outcome of the reciprocal cross and the appearance of the recessive phenotype in male progeny of recessive females are each most consistent with this mode of inheritance. [2 pts] 2b. Parents: X g Y x X G X G [2 pts] F 1 : ♂ X G Y (gray) and ♀ X G X g (gray) [2 pts] F 2 : ♂ X G Y (gray) and X g Y (yellow) in a 1:1 ratio [2 pts] ♀ X G X G (gray) and X G X g (gray) in a 1:1 ratio 2c. The F 1 in Cross 2 are ♂ X g Y (yellow) and ♀ X G X g (gray) [2 pts] and the F 2 are expected to be ♂ X G Y (gray) and X g Y (yellow) in a 1:1 ratio, and ♀ X G X g (gray) and
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MT+1+Key - Biological Sciences 101 Summer Session I 2011...

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