quiz june 20th

quiz june 20th - (46-61.38 2/61.38(78-63.86...

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Ye Jin Yoon (Jane) June 20, 2011 quiz in Stat 1181 (003) a) 44/99 * 100% = 46.5% b) e = (row total) * (column total) / overall total = 186 * 99 / 300 = 61.38 this number shows the expected frequency for each cell (in this case, the YES & Lower Class) under the assumption that the null hypothesis (: socio-economic class and yes/no opinion on the HST are independent to each other) is true. c) o is for observed frequency, e is for expected frequency
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Unformatted text preview: [(46-61.38) 2 /61.38]+[(78-63.86) 2 /63.86]+[(62-60.76) 2 /60.76]+[(53-37.62) 2 /37.62]+[(25-39.14) 2 /39.14]+ [(36-37.24) 2 /37.24] = x 2 18.447 = x 2 d) d.f. = (r-1)(c-1) = (2-1)(3-1) = 2 D.p = 5.991 Since x 2 > D.P., we have enough statistical evidence to reject the null hypothesis. In layman’s terms, different socio-economic classes have significant different behavior about HST referendum (Yes or No)...
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