quiz june 20th

quiz june 20th - (46-61.38 2/61.38(78-63.86...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Ye Jin Yoon (Jane) June 20, 2011 quiz in Stat 1181 (003) a) 44/99 * 100% = 46.5% b) e = (row total) * (column total) / overall total = 186 * 99 / 300 = 61.38 this number shows the expected frequency for each cell (in this case, the YES & Lower Class) under the assumption that the null hypothesis (: socio-economic class and yes/no opinion on the HST are independent to each other) is true. c) o is for observed frequency, e is for expected frequency
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: [(46-61.38) 2 /61.38]+[(78-63.86) 2 /63.86]+[(62-60.76) 2 /60.76]+[(53-37.62) 2 /37.62]+[(25-39.14) 2 /39.14]+ [(36-37.24) 2 /37.24] = x 2 18.447 = x 2 d) d.f. = (r-1)(c-1) = (2-1)(3-1) = 2 D.p = 5.991 Since x 2 > D.P., we have enough statistical evidence to reject the null hypothesis. In layman’s terms, different socio-economic classes have significant different behavior about HST referendum (Yes or No)...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online