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Unformatted text preview: Section 36 1. Working in Z 10 (a) 3 + 3 = 6 (b) 6 + 6 = 2 (c) 7 + 3 = 0 (d) 9 + 8 = 7 (e) 12 + 4 =? Technically, according to the de&nition of Z n on page 310, the number 12 is not in Z 10 , so this addition is not de&ned. Personally, in the context of Z 10 , I think of 12 as being equal to 2 which is in Z 10 . So 12 + 4 = 6 . (f) 3 & 3 = 9 (g) 4 & 4 = 6 (h) 7 & 3 = 1 (i) 5 & 2 = 0 (j) 6 & 6 = 6 (k) 4 & 6 = 4 (l) 4 & 1 = 4 (m) 12 & 5 = 0 , or 12 & 5 is not de&ned (see part ( e ) ) (n) 5 8 = 7 . Im sure that 3 is not an acceptable answer for this textbook because he does not consider 3 to be in Z 10 . Lots of other people would not accept 3 , and I dont either. What is the point of this problem if 3 is an acceptable answer? One could have just as well have answered 21 to part ( h ) . (o) 8 5 = 3 (p) 8 = 7 = 4 because 4 & 7 = 28 = 8 (q) 5 = 9 = 5 because 5 & 9 = 45 = 5 2. Solve for x (a) 3 x = 4 in Z 11 . The answer is x = 5 ....
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This note was uploaded on 07/13/2011 for the course MAD 2104 taught by Professor Staff during the Spring '08 term at FAU.
 Spring '08
 STAFF

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