Unformatted text preview: 50 CDs . (a) How many ways can you load the player so that each tray contains a CD ? You can put any of the 50 CDs in the &rst tray, any of the 49 remaining CDs in the second tray, and so on. So the number of ways you can load the player is 50 & 49 & 48 & 47 & 46 & 45 = 11 ; 441 ; 304 ; 000 . (b) How many ways can you load the player so that exactly one tray contains a CD ? You have to pick one of the 50 CDs to load and one of the 6 trays to put it in. The number of ways you can do this is 50 & 6 = 300 . 3. Calculate the following (a) 100! 98! 100! 98! = 100 & 99 & 98 & 97 & & & & & 1 98 & 97 & & & & & 1 = 100 & 99 = 9900 (b) (51) 3 (51) 3 = 51 & 50 & 49 = 124 ; 950 (c) Q 6 k =3 (2 k ± 1) Q 6 k =3 (2 k ± 1) = 5 & 7 & 9 & 11 = 3465 (d) Q 100 k =1 k k +1 Q 100 k =1 k k +1 = 1 2 & 2 3 & 3 4 & 4 5 & & & & & 98 99 & 99 100 & 100 101 = 1 101...
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 Spring '08
 STAFF
 Self number, Compact Disc, 99, Compact Disc player, consecutive letters

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