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Spring2008test2

# Spring2008test2 - Tcst I EEL 3111C Spring 2MB Dr...

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Unformatted text preview: Tcst # I EEL 3111C Spring 2MB Dr. Sritaastava (1} Amer each of the following questions in the space allotted. 4 {a} Consider switching in an R—C circuit at t = El. At what instant is the magnitude of the capacitor current a maninttnn'? Is your answer 1alralid independent of whewr the capacitor is being charged or discharged after Witching? Justify. ' Vii-e7: Vitae? + E prorated) a: it ,1: .. + ‘ld {5 MHF'rWAi-{ﬁm cuE‘ “Er—:9 - 4 (b) Two indoctor are in parailcl. Derive current divider formula and state clcarhlr under what conditions, if any, it is applicable. J: t ‘ t L -* l~ {43'} + fl 5 viii: L— , o .— t = L L-buj +1; {-ij +L 5 Vet Let, «i L143“; =lilf+s31=e 4 ['3] in this table betﬂwt list typical values ofthc three parameters used to charactelize an op amp, Parameter Non ideal op amp Ideal op amp . F}? F‘ t sir 1:55” Ge Fin: tee -ten:: 41 '5’ ll] - c { 1 R ho lCP—r IEJL- comman ---- -- 4 {c} in the table below, list typical values ofthe three parameters used to chalacterizae an op amp. Parameter "Non ideal op amp Ideal op amp (i) a 105+ 1:95 m R {n -' 1 95:.— tEJLF at: (m) as w r Idiom. w 4 (d) A voltage pulse vim shown below is applied to the circuit: Sketch the capacitor 1Irroltagrc for following two cascs: (i) RC a} 1.; {ii} RC sir: tn_ 4 {e} Which quantith has to be continuous in a capacitor and “my? f- r; ﬁll—ﬁr c’ so: "He—- WEE-nil: LL QanJJfHHGI—cd “ZR—‘14- I'd (2] Cansidcr an ideal up amp circuit shown. 5 (ajFinde -.2_U 33:: C) — 1 m :3 V 5 {in} Find VI] inIEnILsc-f‘fl. 2: (Am + 14m i C, 40 1C} l+‘-f.+‘i'1\'a:¢ 1V3: Kit-1'6 (c) What is the. range c-fvalucs [sf in fur linear operation? Naim-:11 --—':1" VI:- __ 3,5, :5 \r 5 I'EN‘ {cl} IFV. = 3 ‘3, ﬁnd the puwer dﬂliVﬁl'Ed by this vallaga source- ‘1 2 ﬂ :qulgwﬂ ﬂ 4"” ' cage Lia P: V1152ﬂ03?51mw 6% P:+G§3?_5w (3} The switch in the circuit shown below cup-ans at t= ﬂ. Sivan: mm = Emma—3m v far 11 :~ 0, mm = 20 A, 12m} = m A, ﬁnd the fullnwing quantities: 5 (3}iﬂit}fﬁl't}ﬂ. i; EU") 2 LED)" ‘10:.) : )ﬂ‘q IL- . L3: _ L 1 ii %zat‘ .a—‘Illh' 1G 45):" 0+3 #210993 a? ” alu'L- {:1 : lc:—-(lc'c’” E. lﬂy‘aiﬂ o -1 -L- : 10a é Pt 5 {b} vllit} fart 1* IE}. __ l” j: V i E; ii. 10 E. )Qq’b V; :3. —' 1199 E” “latit- - := (6-0"? E“ : “11+- ‘1” Jc ,-L— . .._2r..« 5 {c}lt{l}1‘nrt:~ﬁ. r d\$ﬂﬂ E: 5U.— __ 2:? "F '_' [II {4:} - .20 G I “ﬂaky: EGG :1, J : 2—0 11;: ('19-) 41.51: H {d} 133) fnrt‘eﬂ. " 1 - _ _ 1; Up) I}. Le“; ll (4:) - —L;.-—E— : :1 tar-ﬁe ‘1 {e} Tate] initial energy stared. 1 l L 1 6 (I a '. 'e r: +_. 'e, w[5):320£2e)+_£§( j l :— 45155—3231]— .J (i) Tntel ﬁnal energy.r stared. 1— '1 {La _. 9 IE erh) :— ilc’cig)+ 2.- ( 1-; Lhasa}? {g} Energyr transferred to the hex by using results hf parts (e) and {1]. A w :2 m ( e: j .— w (en 3 :— i—Ger T (h) Energ}F tanefened tn the hex by integrating the pnwer'nheerhed h}; the hex. . =43 p ‘3” Jane M: 5 Vanda: :52mm 5% I? U T, SEEK (4)111: initial voltage on ihe capacitur circuit ShﬂWﬂ below was nag-{El} = ~—3 V. The switch closes at I =ﬂ. 5 S {b} Find vdco} m 5 {*5 c;& aimag. +. q M — iv “7‘”— E-Ha * 5' 1 1:? 56 IE ’ “L :: 14V I CONTINUED .... .. :"i S S [e] Determine the time eenstant 1: fer t} 0. “J2. . + we cues-L HQ: lﬂﬁﬁ “~33— 3:1; Vi :J-Jl VJJIH“ EL+U.r.___.U:—:Cﬁ 3t;- il'i? é; a. ~ “‘5' VJ. Vt+ {91+ .3: : D ‘E’ £6 at D tutti-V ﬁaﬂmﬁw‘m 3h ' 0 EWMEVJVE ' egg; : 6’V3‘20014qgﬁﬁ .- Gez: : iﬂ'w.5' (d) At what time deee the energg.r stored go to zero“? - labrt Hate): iii-thawﬂiﬁa V Nc:c:: W‘ﬁﬁ’m “Ct-[:7 11:} ' Fr [cm-"E 1H : E1 4: : Gtﬂﬁ1i‘3 S : Jilg mg (e) Find the expression for hit) for t 3* D. F IDDI: .. —£: 1; : mwe (EDGE-ii) a ﬂ H I #iaﬁt ‘31 x —_ 40-5 e:- “’1 CONTINUED ---- 5 (1‘) Determine xxx-{t} fer t 2* I]. V = “(L—\$60!; 3 . ""]L-li:‘ Flat-L— : .QQFSE'? EL E’— . _"_lﬂﬁ"ﬁ ' r; 2. L: —- 2 3' .Lfi- \f 'U >4 V '33 5 (3) Of the fellewing quantities, which enee are net cenﬁnueue at t= I]? {M ‘HU‘E 25 952.19% t: e: (min ha}: I 2554.15} :2"? {1:15:- {:33 (ﬁnis “ﬂit _, W we ...
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Spring2008test2 - Tcst I EEL 3111C Spring 2MB Dr...

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