{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

formulas_exam3

# formulas_exam3 - Statistics 101 Formulas Final Exam y= yi n...

This preview shows pages 1–2. Sign up to view the full content.

Statistics 101: Formulas – Final Exam y = Σ y i n s 2 = Σ( y - y ) 2 n - 1 σ y = σ n z = y - μ σ y ± t ( se ) se = s/ n t = y - μ 0 se z = ˆ π - π 0 σ ˆ π σ ˆ π = s π 0 (1 - π 0 ) n ˆ π ± z ( se ) se = q ˆ π (1 - ˆ π ) /n n = π (1 - π ) z M 2 n = σ 2 z M 2 π 2 - ˆ π 1 ) ± z ( se ) , se = s ˆ π 1 (1 - ˆ π 1 ) n 1 + ˆ π 2 (1 - ˆ π 2 ) n 2 t = ( y 2 - y 1 ) /se, ( y 2 - y 1 ) ± t ( se ) se = s s 2 1 n 1 + s 2 2 n 2 χ 2 = Σ ( f 0 - f e ) 2 f e , df = ( r - 1)( c - 1) , f e = (row total)(col. total) /n standardized residual = f o - f e q f e (1 - row prop . )(1 - col . prop . ) 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Bivariate regression models E ( y ) = α + βx ˆ y = a + bx r = b ( s x /s y ) r 2 = ( TSS - SSE ) / ( TSS ) b ± t ( se ) t = b se ( df = n - 2) , se = s q ( x - x ) 2 = s s x n - 1 s = s SSE ( n - 2 s = q SSE/ ( n - 2) = Root MSE Multiple regression models E ( y ) = α + β 1 x 1 + β 2 x 2 + · · · + β k x k ˆ y = a + b 1 x 1 + b 2 x 2 + · · · + b k x k R 2 = ( TSS - SSE ) / ( TSS ) TSS = X ( y - ¯ y ) 2 SSE = X ( y - ˆ y
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern