HW4 Solutions - Homework # 4 Solutions 1) Problem 12.1...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Homework # 4 Solutions 1) Problem 12.1 (Haadat) Solution: Speed Regulation, R = 5% = 0.05 59.7 – 60 = - 0.3 Hz. = -0.3/60 pu. = 0.3/(60*0.05) = 0.1 pu. = 0.1*250 = 25 MW. 2) Problem 12.2 (Haadat) Solution: Let, the load on Gen A = x Then, the load on Gen B = 500 – x Now, the change of frequency = Therefore, Also, Now, equating the frequency deviation, or, or, or, Therefore, Gen A takes up 200 MW Gen B takes up = 500 – 200 = 300 MW. 3) Problem 12.3 (Haadat) Solution:
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Given: Single area-Two Generators-rated at 400 and 800 MVA Speed Regulation for Gen 1, Speed Regulation for Gen 1, Let the common base be 1000 MVA. ( ) = / = . . Load increase pu 130 1000 0 13 pu ) = Case a when D 0 , = . = . . New frequency f 60 0 3 Hz 59 7 Hz : Change in Generations = = . = 0 05 pu 50 MW = = . = . 0 08 pu 80 MW : New Generations ) = . Case a when D 0 804 = , = . = . . New frequency f 60 0 291 Hz 59 709 Hz : Change in Generations
Background image of page 2
= = . pu 48 5 MW = = . . pu 77 6 MW : New Generations ) 4 : Solution
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/14/2011 for the course ECE 522 taught by Professor Tomsovic during the Summer '10 term at University of Florida.

Page1 / 8

HW4 Solutions - Homework # 4 Solutions 1) Problem 12.1...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online