HW6 - % % Homework Assignment 6 % c clear all;...

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% % Homework Assignment 6 % clear all; c disp('Problem 1'); % Problem 1 % Adapted from 3.9 in Grainger and Stevenson into Kundur notation Laa0=2.7656e-3; Laa2=0.3771e-3; Lab0=1.3828e-3; L % Note to get the same result using Grainger's orientation instead of Kundur % Field current is -4000 and a,b,c are shifted 180 degrees (inverted) % Then the d-q axis values are off by a factor of sqrt(2/3) % (Flux in abc coordinates) ifd=4000; degtorad=pi/180; theta=60*degtorad; ia=20e3*sin(theta-pi/6); ib=20e3*sin(theta-pi/6-2*pi/3); ic=20e3*sin(theta-pi/6+2*pi/3); disp('Stator flux linkages'); fluxa=-(Laa0+Laa2*cos(2*theta))*ia+(Lab0+Laa2*cos(2*theta+pi/3))*ib+ . .. (Lab0+Laa2*cos(2*theta-pi/3))*ic+Lafd*cos(theta)*ifd fluxb=-(Laa0+Laa2*cos(2*theta+2*pi/3))*ib+(Lab0+Laa2*cos(2*theta+pi/3))*ia+ . .. (Lab0+Laa2*cos(2*theta-pi))*ic+Lafd*cos(theta-2*pi/3)*ifd fluxc=-(Laa0+Laa2*cos(2*theta-2*pi/3))*ic+(Lab0+Laa2*cos(2*theta-pi/3))*ia+ . .. (Lab0+Laa2*cos(2*theta-pi))*ib+Lafd*cos(theta+2*pi/3)*ifd
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HW6 - % % Homework Assignment 6 % c clear all;...

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