HW9 Problems

# HW9 Problems - — 10.9 UNBALANCED FAULT PROGRAMS 453 9 8...

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Unformatted text preview: — 10.9. UNBALANCED FAULT PROGRAMS 453 9 8 0.0020 0.5924 0 . 5924 10 4 0.0612 1.0217 1.0217 11 7 0 . 3046 1.1067 1 . 1067 Another fault location? Enter ’y’ or ’n’ within single quote -> ’n’ PROBLEMS -phase currents are . Obtain the original unbal- 10.3. The operator a is deﬁned as a = 11120° a ; show that ‘ (1M); =11120° _a o m- = (C) (a — a2)(a2 — a) = 310° (a) vain = ﬁmiwcr The following currents a re given: [1, = 916511609" ance of Z, = 3'24 9 tween phases is Zm = j6 Q. (a) Determine the line currents by mesh analysis without using symmetrical components. FIGURE 1 Circuit for (6) p01 (f) eac 10.8. Th 60' 103 mi (a) (b) (0) FIGURE 10.27 Circuit for Prohlem 10.6. 10.9. A} po C 10.7. A three-phase unbalanced source with the following phase—to-neutral volt- ages ph 300 [—1200 7' Vabc = 200 190° 10.10}: 100 l—30° fan Is applied to the Circuit in Figure 10 28. The load series impedance per phase 10 11 ,1 IS Zs = 10 + 340 and the mutual impedance between phases IS Zm 2 3'5. ' 'Vi: The load and source neutrals are solidly grounded. Determine W (a) The load sequence impedance matrix, Z012 = A‘lzabCA. C (b) The symmetrical components of voltage. ta] (0) The symmetrical components of current. (d) The load phase currents. ph .ied to a 1331' rigure 10.27. :ances. EaCh coupling be‘ symmetrical FIGURE 10.28 Circuit for Problem 10.7. ponents, 53¢ = 3(V012* (f) The com voltages in an unbalanced three-phase supply are Vab = 600136.87° Vbc = 8001126587”, and V . A Y—connected phase is connected to the supply. Deter- mine (a) The symmetrical components of voltage (b) The phase voltages (c) The line currents. 10 9 A generator havmg a solidly l-neutral volt- ...
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HW9 Problems - — 10.9 UNBALANCED FAULT PROGRAMS 453 9 8...

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