Midterm1-PracticeSolutions

Midterm1-PracticeSolutions - gunk km 9.‘vr'L ‘...

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Unformatted text preview: gunk \ km. 9% .‘vr 'L .. ‘ ‘VL’JC. Q .. 4.67% = _ ma) 0.: R m 2 E . 1 IX .. a: (a. 2 3 my. if. 5 5 4.? 4/ 47» C .3 H... I. x x 5 1 3 1k . R L .4 S 3559610ny .. ,2 . Power 33/0“; 7.; xrlltitrla c a E. \ , {ELL 2 Q .55 5%le m... n... r. \u — . 5.3.53. .. = (H .1.) 1 w 1.. a c _: imiL . = H... <0 .. {141.34 a U l : s bud .13I\ IIIII _ “ v 5 m... z. -1. ._.. .4; _ «1 ‘ 91. ii. 5 m... rw ’12 Tull}; : , no .I‘m; 5 9 , {La r... c T113; = ,6. Q. o e . 3 m ,.._ V. _. ,m w P x A. x .3 b m. V; l..\ .f V as.” = _. S 9;. . \\ \‘2 . , 4 E /3 w 8 E c o . u . /\.!.\ \ s q- : \\. If I I 1/. E 2 L .. _ r .\\L . m . x . 2 1.. J 2 :w E a f. 2 L\\ ’3 : U .5 .2. E n— q. —r$2['§3 \Q+E:l§ i; L 2. an? 8 NO VO 2 3 Ch GAN 0 b _ O ; A: a. V 2 4 5 ‘6 o o a 5.4 Q a. w . 31:. II; 1; Nth. . I 3 2 (G E: in \a S 2 D 2 a. 2 , 1 3 E S — v ~ A; M: . n,» .7; a r ,‘ . g. 0?? . .j l V 3 _ L O _ : z c .15 .5 UV 0% \o \O N \ x 0 U .o 3 L 11. Cm E \J M 1:; 19 S 7,1 t 11.3; , 1: M 1 t Z. ‘ 3 ‘ CO <0 UV _ S E 1 n— \. I... _ . d 7.; a a. m: g . . l x c 3 i x. y r J 2 .H: In 0.. via ., J» ||X.4-kv I \4 .14 a c .x 94L 'xril!. I: : . 10% Me 5 IV 5 G a 5 : 5 Q . o . R, g _ _ 10 l a-G—oVC/rvmr 6193):? ‘ Qt ~ Me i sick, $3 c 963,53 ’ "L“ r“: '7‘ -— - ‘ A ‘1va :K‘Z'E. :C.C: 3: )Jv* :Cri ‘E‘JV ”5319 P ’0 I” [I (B o E E \l b .0 g A‘scuezt '3, r: 3'93 -’- CLVT;‘-¥ = 5964'ng __ \ I .11... —fi Ax” H m: 0.0% _ c.\ M _ WW. .. ________. L ‘5‘ \ .1, Al"? c..\ ‘ Crl C3.\ K‘Jr ya 1‘}. \l 0 u? at (,3 .«U 7-; l I U0 U] w \\- AL. PV curve A Yfl'fv A '- Avem. ES m m: M: m, ”(J = G a i, S as {a c a P CO = .1 a” .th :4 K i 5,. \ m t , «mv aw ; m S. x m y... 7 .M a w. 0 w z A, 2 M mm 2 R a. m E .3 7 n. 5 a: O n. : : a m“ t n 3 WT w; X k 5 z. n! n. 0 o O Q .. = 1 Q g . v, \ a. A, R R a CO CO = AU {y L. 3 .33 Q. 2i.o€30 = a 0A, 3 r: as a: = E C ,—\ \II/ a: e o in _ \I 3 AL 3 ., e A J m I a. a . e Rm 7; D\ Qu WI. 5 _ I. v: A _ a x.” V ... u C. -u /\ = __ .nfi 9. + D. A. / 1:I\ ‘ w~~53a3= -[LL-v'r’TEa Mw' ! , ,, _ . . N2 oyTH/e Vac—{Lia's g-E AC5, fun, Cl"! 7%?‘35. {£21123 1% 6; kill/i fl'w—t 33¢ .morase 13 m 93.4- 33pr be £161 1w? QQ'UJ‘ '72‘\»., L»A_ ‘ ‘“ W “* ~v waua, \0 areas 6. Short Answer (20 points) (a) What are the known variables (i.e., specified) at each bus type in the power flow equations? Slack —a lVl / 6 (N Generator we Wl, v Load .3 6;; ,6;- (b) What are the unknown variables (i.e., not specified) at each bus type in the power flow equations? Slack ".29 P A; Generator we? g, 3 Load “OJ-I! i g ”5363 (0) Which of the two load flow algorithms (i.e., fast decoupled or full Newton-Raphson) do you expect to converge in fewer iterations? State reason. MR Convergeg @as‘lfe'r 0.3 it use: sisiw Ingarwztétan, in 310% of; 33:33th +:; ecfazfir2¢_ Sal-t.s.‘¥ian.s. (d) Which of the two load flow algorithms (i.e., fast decoupled or full Newton-Raphson) do you expect to converge fastest (CPU time)7for a moderatelyloaded system? State reason. FD Gamer-egg 4’ ‘ ‘ ‘ ‘a; . m.u-— ..L ..,.._ q ~, n . ‘ . e, 1‘05“" SM“??? 3mm?“ ‘“*"" 7““ ““3”"“1-3 “"- 30415“ *0 wld’ ,1 Ts )YLVEI’SE Is Calenlaitmi 0?qu e.) (e) In the power system security framework, what is meant by a secure operating point? (Be Om J'W'l‘ - ~ . A 4. r ‘ 3 , ~ ‘ : spec1fic.) Seawm or? avg-EMA Pawn— W3 "5ka «,L‘Iw, 333‘0" ”Ema-ME VIC—Ne, Tollomwfi CK. cia‘fiu; asewfi > . ‘ . . ‘ - ~ ‘ . ~ - Let all armament rewarewx :uw‘mn *‘Wt‘fi' aflfififlwfi lWW‘tin Gaul "rid-I: 3‘53'ii‘2‘rk‘k IS Shame §or ex g - 1:. x a ‘3 g Pffit’heci (t) Consider a small system with two areas, say area A and area B. Area A is being a good as} crit- citizen on the frequency control With a Bias setting larger than the ideal setting (i.e.5 above the ’3‘”W“’" :1 natural governor response). Area B has the Bias setting exactly at the natural governor response. If Area B experiences an increase in load, then the initial Area Control Error (ACE) for area A will be: i) greater than zero (i.e., AGC sends lower pulses to the generators in area A) ii) zero 4?; less than zero (i.e., AGC sends raise pulses to the generators in area A) ...
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