Swing Equation

# Swing Equation - δ ∆ ¨ δ t = − πf s H P max e cos...

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Swing Equation - Simple non-linear and linear dynamics March 2, 2011 POWER SYSTEM DYNAMICS P e ( δ, t )= P max e sin δ ( t ) P max e = E a V X eq ¨ δ ( t )= πf s H ( P m P e ( δ, t )) A a = ° δ cc δ 0 ( P m P ° e ( δ, t )) A d = ° δ 2 δ cc ( P °° e ( δ, t ) P m ) A a = A d Runge-Kutta Integration K ω, 1 = πf H ( P m P ° max e sin( δ ( t ))) K δ, 1 = ω ( t ) K ω, 2 = πf H ( P m P ° max e sin( δ ( t )+ K δ, 1 t 2 )) K δ, 2 = ω ( t )+ K ω, 1 t 2 K ω, 3 = πf H ( P m P ° max e sin( δ ( t )+ K δ, 2 t 2 )) K δ, 3 = ω ( t )+ K ω, 2 t 2 K ω, 4 = πf H ( P m P ° max e sin( δ ( t )+ K δ, 3 t )) 1

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K δ, 4 = ω ( t )+ K ω, 3 t K ω = 1 6 ( K ω, 1 +2 K ω, 2 +2 K ω, 3 + K ω, 4 ) K δ = 1 6 ( K δ, 1 +2 K δ, 2 +2 K δ, 3 + K δ, 4 ) ω ( t +∆ t )= ω ( t )+ K ω t δ ( t +∆ t )= δ ( t )+ K δ t Small signal analysis ¨ δ ( t )= πf s H P max e cos( δ 0 )∆ δ ( t ) ω rf = ° πf s H P max e cos(
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Unformatted text preview: δ ) ∆ ¨ δ ( t ) = − πf s H P max e cos( δ )∆ δ ( t ) − πf s H P D ∆ ˙ δ ( t ) K 1 = P max e cos( δ ) K D = P D ω o ∆ ˙ ω r ( t ) = − K 1 2 H ∆ δ ( t ) − K D 2 H ∆ ω r ( t ) ∆ ˙ δ ( t ) = ω s ∆ ω r ( t ) ( s 2 + s K D 2 H + K 1 ω o 2 H )∆ δ ( s ) = 0 s = 1 4 H ± − K D ± ² K 2 D − 8 K 1 Hω s ³ = 0 2...
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## This note was uploaded on 07/14/2011 for the course ECE 522 taught by Professor Tomsovic during the Summer '10 term at University of Florida.

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Swing Equation - δ ∆ ¨ δ t = − πf s H P max e cos...

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