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Unformatted text preview: the questions: Cov Z*X = 1/2[Cov Z*S + Cov Z*D] = ½ [.25 + .375] = .3125 Cov R*A = 1/2[Cov R*R + Cov R*T] =½ [1 + .5] = .75 Cov A*S = 1/2[Cov A*R + Cov A*D] = ½ [.75 + 1] = .875 Cov S*S = 1 + 1/2[CovR*D] That is 1 + 1/2Cov(Parents of S) = 1 + F S = 1 + .5[.75] = 1.375 Cov S*X = 1/2[Cov S*S + Cov S*D] =½ [1.375 + 1.0625] = 1.21875 Cov X*X = 1 + 1/2[Cov S*D] = 1 + F X = 1 + ½ [1.0625] = 1.53125 a. What is the level of inbreeding to be expected in the mating of Z to X? ½ Cov Z*X = ½ * .3125 = .15625 b. What animal should cow D be mated to that would result in the lowest level of inbreeding? Z, this mating would yield progeny with an inbreeding coefficient of only .125. c. What is the inbreeding coefficient of X? .53125 d. How much inbreeding would be expected in the mating of X back to her sire, S? ½ * Cov X*S = ½ * 1.21875 = .609375...
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 Spring '09
 Olson
 Mating, Selective breeding, Inbreeding, Exogamy

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