Chapter 1 - 10 1 C. 2.0 × 10 1 D. 20.13 E. 2.012 × 10 1...

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Chapter 1 1. 13.2 nm is equal to A. 1.32 × 10 6 cm B. 1.32 × 10 6 mm C. 1.32 × 10 8 cm D. 1.32 × 10 8 mm E. None of the above answers is correct 2. A 112.6 g mass of unknown material is submersed in 102 mL of water to yield a final volume of 126 mL. The apparent density of the unknown material is A. 0.908 g/mL B. 1.10 g/mL C. 0.21 g/mL D. Not determinable from the information given E. None of the above answers is correct 3. The answer to the calculation ( )( )( ) 12949552 . 20 925 . 8 6 . 4 13 . 18 0 . 94 63 . 1 025 . 1 = + to the correct number of significant figures is A. 20 B. 2.01 ×
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Unformatted text preview: 10 1 C. 2.0 × 10 1 D. 20.13 E. 2.012 × 10 1 4. The result of adding 1.17 × 10 − 2 and 8 × 10 − 3 is, to the correct number of significant figures A. 1.9 × 10 − 2 B. 1.97 × 10 − 2 C. 2.0 × 10 − 2 D. 0.02 E. None of the above answers is correct 5. (107.36 – 99.2) (5.4033 × 10 5 ) = 4.4090928 × 10 6 The above calculation, when expressed to the correct number of significant figures and properly rounded, should be written A. 4.4 × 10 6 B. 4.40 × 10 6 C. 4.41 × 10 6 D. 4.4090 × 10 6 E. 4.4091 × 10 6...
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This note was uploaded on 07/16/2011 for the course CHEM 110 taught by Professor Hofmann,brucerob during the Spring '08 term at Penn State.

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