21_PartUniversity Physics Solution

21_PartUniversity Physics Solution - Units, Physical...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Units, Physical Quantities and Vectors 1-21 ( ) (0 148.5 m 242.5 m) 94.0 m yy y y DA B C =− + + =− − + 22 x y DD D =+ ( 108.5 m) ( 94.0 m) 144 m D + = 94.0 m tan 0.8664 108.5 m y x D D θ == = 180 40.9 220.9 = °+ °= ° ( D " is in the third quadrant since both x D and y D are negative.) Figure 1.73b The direction of D " can also be specified in terms of 180 40.9 ; φ = −° = ° D " is 41 ° south of west. EVALUATE: The vector addition diagram, approximately to scale, is Vector D " in this diagram agrees qualitatively with our calculation using components. Figure 1.73c 1.74. IDENTIFY: Solve for one of the vectors in the vector sum. Use components. SET UP: Use coordinates for which x + is east and y + is north. The vector displacements are: 2.00 km, 0 of east; 3.50 m, 45 south of east; AB $ $ and 5.80 m, 0 east R $ EXECUTE: ( ) ( )( ) 5.80 km 2.00 km 3.50 km cos45 1.33 km xxxx CRAB =−−= ° = ; y yyy =−− () ( ) 0 km 0 km 3.50 km sin45 2.47 km ° = ; ( ) 1.33 km 2.47 km 2.81 km C = ; 1 tan 2.47 km 1.33 km 61.7 north of east. ⎡⎤ ° ⎣⎦ The vector addition diagram in Figure 1.74 shows good qualitative agreement with these values. EVALUATE: The third leg lies in the first quadrant since its x and y components are both positive. Figure 1.74 1.75. IDENTIFY: The sum of the vector forces on the beam sum to zero, so their x components and their y components sum to zero. Solve for the components of F " . SET UP: The forces on the beam are sketched in Figure 1.75a. Choose coordinates as shown in the sketch. The 100-N pull makes an angle of 30.0 40.0 70.0 += °°° with the horizontal. F " and the 100-N pull have been replaced by their x and y components. EXECUTE: (a) The sum of the x -components is equal to zero gives (100 N)cos70.0 0 x F + = ° and 34.2 N x F . The sum of the y -components is equal to zero gives (100 N)sin70.0 124 N 0 y F + −= ° and 30.0 N y F . F " and its components are sketched in Figure 1.75b. 45.5 N xy FF F = . 30.0 N tan 34.2 N y x F F and 41.3 = ° . F " is directed at 41.3 ° above the x -axis in Figure 1.75a. (b) The vector addition diagram is given in Figure 1.75c. F " determined from the diagram agrees with F " calculated in part (a) using components.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1-22 Chapter 1 EVALUATE: The vertical component of the 100 N pull is less than the 124 N weight so F " must have an upward component if all three forces balance. Figure 1.75 1.76. IDENTIFY: The four displacements return her to her starting point, so ( ) D= A+B+C " " " " , where A " , B " and C " are in the three given displacements and D " is the displacement for her return.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/16/2011 for the course PHY 2053 taught by Professor Buchler during the Spring '06 term at University of Florida.

Page1 / 5

21_PartUniversity Physics Solution - Units, Physical...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online