966_PartUniversity Physics Solution

# 966_PartUniversity Physics Solution - 34-4 34.12 Chapter 34...

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34-4 Chapter 34 34.12. IDENTIFY: sf s s f ′ = and f m f s = . SET UP: With f f =− , s f s s f ′=− + and f m s f = + . EXECUTE: The graphs are given in Figure 34.12. (a) 0for 0. sf s >− < < (b) 0 for s and 0. s << < (c) If the object is at infinity, the image is at the outward going focal point. (d) If the object is next to the mirror, then the image is also at the mirror (e) The image is erect (magnification greater than zero) for . s f (f) The image is inverted (magnification less than zero) for . s f < − (g) The image is larger than the object (magnification greater than one) for 20 . fs (h) The image is smaller than the object (magnification less than one) for 0and 2 . s >< EVALUATE: For a real image (0 ) s > , the image formed by a convex mirror is always virtual and smaller than the object. Figure 34.12 34.13. IDENTIFY: 11 1 s += and ys m ′′ == . SET UP: 2.00 m =+ and 1.25 cm s = . An erect image must be virtual. EXECUTE: (a) sf s s f ′ = and f m s f . For a concave mirror, m can be larger than 1.00. For a convex mirror, f f so f m s f + and m is always less than 1.00. The mirror must be concave ( 0) f > . (b) 1 s s f ss ′ + = . ss f s s = + . 2.00 s m s and 2.00 s s ′ = − . (2 . 0 0) 2.00 2.50 cm 2.00 ss + = + . 25 . 0 0 c m Rf + . (c) The principal ray diagram is drawn in Figure 34.13.

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Geometric Optics 34-5 EVALUATE: The principal-ray diagram agrees with the description from the equations. Figure 34.13 34.14. IDENTIFY: Apply 11 1 s sf += and s m s = − . SET UP: For a concave mirror, 0 R > . 32.0 cm R = and 16.0 cm 2 R f == . EXECUTE: (a) s . (12.0 cm)(16.0 cm) 48.0 cm 12.0 cm 16.0 cm sf s = −− . 48.0 cm 4.00 12.0 cm s m s =− =+ . (b) 48.0 cm s ′=− , so the image is 48.0 cm to the right of the mirror. 0 s ′ < so the image is virtual. (c) The principal-ray diagram is sketched in Figure 34.14. The rules for principal rays apply only to paraxial rays. Principal ray 2, that travels to the mirror along a line that passes through the focus, makes a large angle with the optic axis and is not described well by the paraxial approximation. Therefore, principal ray 2 is not included in the sketch. EVALUATE: A concave mirror forms a virtual image whenever s f < . Figure 34.14 34.15. IDENTIFY: Apply Eq.(34.11), with . R s →∞ is the apparent depth.
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966_PartUniversity Physics Solution - 34-4 34.12 Chapter 34...

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