# HW2 - Problem 5.8 Estimate the probability of having 4 cars...

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Unformatted text preview: Problem 5.8 Estimate the probability of having 4 cars in an interval. := set: - CH1) WM 13) 3500 {Ea-525i DIS E43.003541 1 pt In 0.6 qz= ( ] q=141_g vehih —O.C|[136 q 1 t 3: = (1039 vehr‘s F3 qsec 3600 qsec during 30 sec intervals: x:=30-qsec x=1_182 yin-e— F’ini := PM) = 0.025 1p“: Determine how many of these 120 intervals have 3 cars arriving. t2=20 SEC Pam 18 _ 120 n —?-.-t ".-t Pm = U 1' e n! [:-.-t}”-e"‘"‘_ 10 0- ' 120 3’. = 0.095 Vishe's P{3)=U.1TDT P[3}-120=20.48 intervals Extra 1,20 =1.897 vehe'ZD s 0.00 = 5.591 vethm 03600 = 341.5 vehfh _q[ Pm) = 63600 4020) 18 3000 _ : e 20 0.15: e— q(D.00556) |n[D.15) = —q{0.00556) |n{D.15) 0.00550 q:= q=3412 100 0.5 pt 1pt 0.5 pt Problem 5.9 (Given) {Eq. 5.23) {EC}. 526) Problem 5.10 Determine gercentages for headwags. vehicles ;= 1 .9 time ;= 20 sec (given) h' | q: we. Ices (1:0095 tlme tgreatz=10 tless := a (glven) _ . E .526 P0) ;= 9 qt ( q ’ P(h 2 10) P'It ‘ 0 387 Pth 2:10): 0387 1 m i great} = - ' P(h 2 6) Pq’tless'] = 0.566 P(h<6)=1—P(h=_>6) less] 1 — P['t ' = 0.434 Pth < 6) = 0.434 1F” Problem 5.11 Determine the Erobability of an accident. 0.5 pt q := 280 t:=1_5 + 2.5 —> 4.0 (given) — -t ﬁ {Eq. 5.26) P(h :3 4) = e _ 83600 = 0.733 P(h<4):1—P(h24) 15” _ q.[ i _ 33600 = [1257 Probability ofan accident 2 0.267 1 pt Problem 5.12 Determine the driver reaction times that would make the Erobability of an accident occuring egual to {1.15. q := 3280 (given) wewant P(h<4):u_15 30: 0.5 pt P(h 2 t] = 0.85 __q.i 0.35: 33500 iEq 525i i=2.09 s 1 pt so the driver reaction time should be: t—1.5=D.59 1m ...
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HW2 - Problem 5.8 Estimate the probability of having 4 cars...

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