This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 36225  Homework 1 SOLUTIONS1.12 points: 2 for each part(i) The document reaches its destination on time (i.e., ontime delivery by at least one ofthe three services).A1∪A2∪A3(ii) The document does not reach its destination on time.A1∩A2∩A3orA1∪A2∪A3(iii) The document reaches its destination on timeonlyby service I and service II.A1∩A2∩A3(iv) The document reaches its destination on time by exactly one of the services (i.e.,onlyby service I, oronlyby service II, oronlyby service III):(A1∩A2∩A3)∪(A1∩A2∩A3)∪(A1∩A2∩A3)(v) The document reaches its destination on time by all three services:A1∩A2∩A3(vi) The document reaches its destination on time, but not by all three services:(A1∪A2∪A3)∩(A1∩A2∩A3)2.10 points: (a) 3 points (b) 2 points (c) 5 points (5*1)(a) List all the possible outcomes in the sample space for this situation.There are six possible outcomes for this situation. Recall from the hint that (2, 1, 3)means that executive 1 picks up the phone of executive 2, executive 2 picks up the phoneof executive 1, and executive 3 picks up his own phone. So, the possible outcomes are:S={(1,2,3), (1,3,2), (2,1,3), (2,3,1), (3,1,2), (3,2,1)}.(b) Assign reasonable probabilities to the sample points. Justify your answer.Since the executives picked up a phone at random, all the 6 possible outcomes in thesample space are equally likely with probability 1/6. Therefore...(c) Find the probabilities of the following events.i. Nobody gets the correct phone.The event that nobody gets the correct phone happens in 2 out of the 6 outcomesin the sample space – (2,3,1) and (3,1,2). So,P(nobody gets the correct phone) =26=13.ii. Exactly one person gets the correct phone.The event that exactly one person gets the correct phone happens in 3 of the 6outcomes in the sample space:(1,3,2): only executive 1 gets the correct phone.(3,2,1): only executive 2 gets the correct phone.(2,1,3): only executive 3 gets the correct phone.Again, since we have equally likely outcomes,P(exactly one person gets the correct phone) =36=12.1iii. Exactly two people get the correct phone.The event that exactly two people get the correct phone means that two peopleget the correct phoneandone gets it incorrect. But since there are three people in all, this event is not possible. Thus, it has probability equal to 0, i.e.,P(exactly two people get the correct phone) = 0.(exactly two people get the correct phone) = 0....
View
Full
Document
 Summer '09
 TOM
 Probability theory, Fraction, Zagreb

Click to edit the document details