FE_05F_s - ME 466 — Machine Design SOLUTION Fall...

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Unformatted text preview: ME 466 — Machine Design SOLUTION Fall Semester, 2005 Final Exam, 200 Points, Open Book 1. (20 Points) A shown shaft transmits 2.5 horsepower at a speed of 600 rpm. The bearing at B is, designed to take all of the axial load. Determine the following: y 5" dia bevel gear L Maximum Bendin _ W , A _ Maximum Shear ' r “s _ 1;, I f I w e. ,, / . , Maximum Bearing . _ Radial Load “133 M u ’. Maximum Bearing . _ ‘ E " (pm, : we 7‘" =3 a,§:;26'7§§§,/=>7’=153I~/6 3" (9 Force; znysarawt mam 9 Made} $5,: mm 115%?“ 17’5‘77/5 1,51%: ac; => pc : WM G] W . ‘7‘ Q $h3=fl= 77QJ/+éf(2) @ XZ Paw/mt [291 9:0 z/ayp/ 5 DZ /(2 Mr 7,9,5) J" J — [7m + ow 4—,? 2 z B 5 Way ’le "'07=$’7/" M M “y ” > a Y I I i ’63 ‘4’ By:lfi/$ b :47716/5’ “2 3””; - fl 0 @ lie/2 A; emf/3 r vets/“fl I i _ a ,3 '51}!ng v3,=m;°=l?o u Bahama/345‘ — 33/5 ’3“ v,» 40‘ mi“ = In 2. (20 Pornts) A full journal bearing has a diameter of 1.50 i ch, Oil Grade Selection $4530 m at is 0.75 inch long, and supports a load of 300 lb. The speed is 2000 rpm, and the radial clearance is 0.0012 inch. The J’ Sideflow loss I .2 a ; 1 {y / . . f . . . . . 33 4 9 rmmmum 11m th1ckness that should be used With th1s beanng IS 0 0.00030 1nch. The operatmg temperature 15 to be 160°F. 3%;7 Determine the grade of oil required, the friction coefficient, the 5 power loss, the flow side loss, and the oil temperature rise of the / ' . V7 W 19“ oil. ' _ 1’}; @ Ao/c: %:$%:._f . '{ ~ @ 5: é fl: gig-{KC}: 5 lugg/mgyny . . , P r Q/W’F (a, 12,6) Jae SJEJ’!) G7 fiend/W F7 “"4” 4‘: £3 (%/=9.3(_—-3"”.”7§ ) am” 7': #FR = ,aaifi(yaa),7f= L57”. // I17 5 alt/w Fly/mi gig/7 '} ) Q: 5—,} chL: 5:}62)7(,Jp/Q)()9g1fl79= .//?H/5‘ \ i as: Igfa : i/flhizr @M?’ 3-29 (if! , .r—IPW“ - _,._/f_. z I AT c? Gr '2 m A Jag/fl 9‘? F P1317 \ MAE 466 - Machine Design F inal Exam - Fall Semester, 2005 page 2 3. (20 Points) An ordinary deep groove ball bearing is to be used on a shaft at a location where the radial load is 360 pounds and the thrust loading is -250 pounds. The shaft (machined from 1020 steel) runs at 2500 rpm and can be considered to operate with mo - 1 - 0 heavy impact. It is to operate for 4000 hours with no more than a 5% bearing failure rate. Select a . all bearing to use in this application. m Eff, = £5; ’~‘. (77 Bearing: e? H” L I} ' ék/V Cm, : Fe K4 (MLR > —~ Fe .— )60 [1+ /,//5- {Jig/232] = 517,7; : on, ' z JFWIL" (EM 4000/w : w E,” ' mm M’ ‘— m h, éflflx/fl : J‘alco’z) M; K4 " 6‘3)7WM K, = , 6) E, W. a any : 7/2/4/ flow/j) \ (34-556 Ave) C —‘ /fl,6 4. (20 Points) A load of 1,500 pounds is to be lifted a distance of 4 feet in 20 seconds. A power screw is used which has a 1.25 inch double threaded Acme screw of standard proportions. The collar has an outside diameter of 2.5 inches and an inside diameter of 1.50 inches. The rumiing coefficient of friction for the threads is 0.15 and for the collar is 0.10. Determine the power required by the screw a . '. - I ~ o . . Tag/Q [4,: m; "40,", Au; 5' fine/y/azf r'. f:,&0 /’ @ L=aM=,?’d” 5154— Z = tor—3:9: /./5‘” .cc: .M) j,” «hex: My” 1‘5""- dc: anrdr ; 02.0” A E V471}; MK/ 7 7w: {TA +Lm'o(n 7, a 7m, mag «,4. ; hwy/r) JIWZ/f) +,4m/zr + 9‘ 7777. mar/e 5‘ ~ .Ifflsf) ‘1 17:19 I 4 ' m” 3.99 1‘ ’MM 32? ‘/4 t A331,, /5 + Ham /5 r In 32%“ 48mm _. we ~ my)». - 5'! . 4f H/mt/ pits/49V 3” 5W}: Mir/{p : 7n _~ MP m 630.)? MAE 466 - Machine Design Final Exam - Fall Semester, 2005 page 3 5. (30 Points) The force, F(t), varies from a low of 200 pounds to a high of 600 pounds. The stub shaft is made from 414%A machined to shape and then heat treated by quenching and tempering at 900°F. Determine the factor of Safety of the bracket’s stub shaft in 0 this application based onalife of 100 thous ndc cles. / ,4, 0,2 5“ = kay’ "L‘\/ l’ . S)’: 05er FS= 3‘0 I 1"dia " ‘ ' fl: $9 .51.. = Wilts? ~ SF); (64-— 9465131. 592=5£6 » (M II}; =' /n 0%)]; ),13”7‘ £26574) Allpartsaremachined W=QF ’6 7 [I 5.76 '9 1‘ 3 1/32" fillet radius $6, : /d :: 79km (49mg; CM/pmené‘ F“: Wig/M: ym @ yawn/firm . fl ’ Limo” 200 = [IC- t g 11¢=39kfil fli=fikrp " 3" 7UP 777,7)" y F Well/<5: 4;:6/67' /, = L; ._ C , 7; 7 — 17%;: : {fa/1:52; dwi— @eg:tdé"l<{f“”m/v 33' "’ . @ {teams ’4’ Ky :10?) ’44)? HQ ’5; a \_,/7+19,f¢7/I5""’€~ - V‘I "3 ‘ ,7 - W1 : AHM. F,79.2rk=.).l k5= /.7 *‘i‘g/l’ ‘95 — “*7” pg EM ? =1” 7,: ,9; @Qpnin 5,; r e: “ml-aw xix/.67 cm I. geifJf-f; 2:, 7’: twig/Haw" a/J mg; a7”: U) L ~ ’3" 7* ,fl ' a“ waf F5 31,77 6. (20 Points) A 3/4-16 SAE grade 8 bolt is preloaded to 90% of its proof strength and then a steady external axial load of 15,000 pounds is applied. Assume that the clamped part is 2.0 inches thick steel and the bolt WEI: Based on proof strength, what is the factor of safety for the 15,000 pound load? 77’d L g It A”: / g r 5 'Wln ‘ "‘ 5 Es = A5 71/ m, 4 ; 373 y » ._ a 7:1; lfl/ 3;: : AMA/9' Q Ba/l‘ MUG Lfle/ @P’el/f’: I9A7$=19fi47mk 6’4ny 1 7:55): C Lw‘li' 09:14 'P —Fe’5'z W 3 i new” V 5 " Mr ' a . k”: ALE: (Vfdfar/o : Kalli/1% : '45”; I, 3 A AC: d“+.m/j+.m,"~ *4 s p?» = .7;‘+,m7/{.2) map) r G ,DW : aim I6 I llgqfln ‘{ x/fl Phky < P}; 'II no' raid/1417,01, : $5“: /, m (fox/0’): 37,4411 “C a V A @f»: ' I ' ‘ I )0va z l (50:54 3'13— =.I?5’ f5: 7r—ifl/ .1574 61% M2 +0an 1/57 a \ MAE 466 - Machine Design Final Exam - Fall Semester, 2005 page 4 7. (20 Polnts) hehcal compress1on sprlng. 1s shown I Outside Diameter - full Slze. It 1s made from 011 tempered w1re. _ _ Complete the cable of spring characteristics giver w Spring Rate 48/ / [o- (c' Solid Height /, M " Force to Fully Compress /5 p ' Will the spring buckle when . . YES ® 1t 1s fully compressed? . l (Justi our answer!) one 6 0 ill the spring yield when it is fully compressed? (Justi our answer!) @Ly =/VTp/:f/,s9/j =Z/7 ” (2/ Jaw/Dew/ :' M71? 0 =01) w! : 7,742 @ PM 5 ML? “9):” [21/7]; Jam @ Ctp/Arilé—J :24 @Ljfz Efim;/'/§ fizz/J ‘ “my 7 @ Kfe/rt'felw 72k; 35%:Wm) @ K 1 £11: : //fv// :e 0 : 3/735], - W'are)’ 309M 876,760 3 ,237”: éflm [1/94/1'7 S’wx/flksl. : 0W M415 7§=.‘/f$«: fer/<7; 8. (20 Points) Determine the maximum force, Fm, which may be applied to the eyebolt shown if the ‘ um _ the material can withstand is 25 si. F max = 330 g __/, (A? i F V_ 75-- {2.1— , 5w" M = 56.1wa Q Mm ll/orrw/ ffrrr; [lime " c)? ’0‘} “ix :4", 57%;; flew-z Egan): "£37137. S‘I‘reg’gg ML I $625“; w 4 é .197; 3 {’r‘vm Ej‘zie (I! kl'x/l) ,1 = *4" o" /<{ IN; , .5140: 3.2 9/5/— , WW ' ‘3 vmmi’ f 7763727“ ‘ ( 2/,3 (/05,£F)~L 9,]; ; Haj}: F: 333/5 ® MAE 466 — Machine Design Final Exam - Fall Semester, 2005 page 5 9. (30 Points) The state of stress at a critical point on the surface of a machine member is determined from strain gage analysis to be as shown on the stress element to the right. The geometric stress concentrations at this location are known to be 2.70 for the normal stresses and 1.80 for the shear Mc/a fl’e’fi stress. Determine the factor of safety of this part if the material is: (a) 6061-T6 aluminum (Appendix 010) F S = 6 y (b) A390-T6 permanent mold cast aluminum F S = I (Appendix C-II) 8 ksi (a) 60 / 7'6 3 = W M % ex,me : /7Z 444% 5“ = W2” (/55 A/M/Mc 57795293“ t/ = MM“ “W” - 0.¢a_rfw~__._\z,5/Wfl I , Ms kw a; : I é ' l , 5/47 a 9 m : KW)"; {(9%)}. glammng)‘ : (NM/cg 5‘ 40km, F 9 “Z : Z / 5 0; me C 5/ C5) A37fl" 75 5,: 45553 ge/Wflg/u /? ,’, o/rff/é/ “ (5' ‘ VSEFM flee/266$ 5w 2’ < g 41:1: =:> %“r Q?l - 07=<7+fi=‘%W 7 .q :7. s" waver—WW Rig/ . Mad, gee/fla/Ir nary? ' - ,m [air/flay F5: 3“ 2 E‘fl‘f. :% ...
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This note was uploaded on 07/19/2011 for the course MAE 466 taught by Professor Wallace during the Fall '09 term at University of Alabama - Huntsville.

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FE_05F_s - ME 466 — Machine Design SOLUTION Fall...

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