# Sol2 - UAHuntsville Spring 2010 PH 113 Homework Solutions...

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UAHuntsville Spring, 2010 PH 113: Homework Solutions No. 2 Solution 7: The sum of the kinetic and potential powers is then dE dt = dK dt + dP dt = = 1 2 μ v ω 2 y m 2 cos 2 kx t ( ) + 1 2 v 2 y m 2 sin 2 kx t ( ) = = 1 2 v 2 y m 2 Solution 8: Solution 9:

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Solution 10:
Solution 11: Wave fronts from either source are concentric circles (for each source) of equal phase. As the two sources are coherent, waves from either source will have the same phase at the same distance from their respective source. If we plot around both sources their respective wave fronts at full wavelength increments, the intersection points will lie along the antinodal lines, curves along which interference is fully constructive. If we plot the wave fronts around one source, and around the other the fronts corresponding to a half wavelength, we similarly find the nodal lines, the curves along which interference is fully destructive. In this picture all the circles are full wavelength separated from the neighboring concentric circle.

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Sol2 - UAHuntsville Spring 2010 PH 113 Homework Solutions...

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