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Unformatted text preview: 8.18 10 V 81.8 kV. 2 2 1.60 10 C p m v V e = = = = Solution 55: (a) For the first and second case (labeled 1 and 2) we have eV 01 = hc / 1 , eV 02 = hc / 2 , from which h and can be determined. Thus, ( 29 ( 29 ( 29 ( 29 ( 29 1 2 15 1 1 1 1 17 1 2 1.85eV 0.820eV 4.12 10 eV s. 3.00 10 nm/s 300nm 400nm e V V h c= = = l l  (b) The work function is === 3 0820 185 300 400 2 27 2 2 1 1 1 2 ( ) ( . ( . . V V l l l l eV)(400 nm) eV)(300 nm) nm nm eV. (c) Let = hc / max to obtain max . = = = hc F 1240 2 27 545 eV nm eV nm. Solution 56: Solution 57: 2 = 1 1v 2 c 2 v = c 11 g 2 p = gmv = gmc 11 g 2 = mc g 2 1 Solution 58: Solution 59:...
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 Spring '09
 LIORBURKO
 Physics, Work, Photon

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