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Unformatted text preview: 2 ] is decreasing at 0.23 M/s, at what rate is [H 2 O] increasing?- because [O 2 ] is decreasing, the change in its concentration must be negative, so we substitute the negative value into the expression and solve for [H 2 O]/t: [H 2 O]/t = [O 2 ]/t = = ( 0.23 M/s) = 0.23 M/s [H 2 O]/t = 2(0.23 M/s) = 0.46 M/s Problem 2 Consider the reaction between NO(g) and O 2 (g) to form N 2 O 3 (g). 1. Express the rate in terms of changes in each reactant and product with time:- first, balance the reaction: 4 NO(g) + O 2 (g) 2 N 2 O 3 (g)- Rate = 1/4 [NO]/t = [O 2 ]/t = [N 2 O 3 ]/t 2. How fast is [O 2 ] decreasing when [NO] is decreasing at a rate of 1.60x10-4 M/s?- [O 2 ]/t = 1/4 [NO]/t = 1/4 (1.60x10-4 M/s) = 4.00x10-5 M/s...
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This note was uploaded on 07/15/2011 for the course CHEM 2045 taught by Professor Gower during the Spring '11 term at University of Florida.
- Spring '11