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Unformatted text preview: wasted due to collisions? Solution. Also, the fraction of time (1-p) no one sends is wasted. The successful fraction is np(1-p) . n n-1 Problem 14. In Fig. 1-19 a service is shown. Any other services? If so, where? If not, why not? Solution. If k-1 is not the lowest layer, layer k-2 can provide service to layer k-1. Similarly, layer k+1 might be providing service to layer k+2, if there is such a layer . Problem 15. If p is probability a frame will not be received successfully, what is the mean number of times sent per success? Problem 14. In Fig. 1-19 a service is shown. Any other services? If so, where? If not, why not? Solution. If n frames are sent, about n(1-p) will be successful. sent/successful = 1/(1-p) = mean number of frames per success....
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- Spring '11