Unformatted text preview: Hypothesized Me df = 7 df 7 t = 1.32 t Stat 1.3206 p-value = 0.114 P(T<=t) one-tail 0.11 t Critical one-tail 1.89 Conclusion: Do Not Reject Ho P(T<=t) two-tail 0.23 t Critical two-tail 2.36 Business Answer: These samples do not provide sufficent evidence to be able to conclude that the average cost to fly out of Dayton, Ohio is more than the cost to fly out of Louisville, Kentucky. B) Business Question: Is there a difference in the average cost of flying out of Dayton compared to Louisville? Reject Rule: Reject Ho if t > 2.36 Calculations: p-value = 0.23 t = (x-bar1 - x-bar2) / (s1 2 /8 + s2 2 /8)^.5 and if Ho is true: and D = L this is t distributed with df we can calculate μ μ...
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- Spring '07
- Statistics, Statistical hypothesis testing, Dayton, Louisville, Dayton Louisville