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HWK #10 NEW

# HWK #10 NEW - Hypothesized Me df = 7 df 7 t = 1.32 t Stat...

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Homework #10 Exercise #24 on Page 429 A) Business Issue: Flight Cost of different Airports Business Question: Is it more costly (on average) to fly out of Dayton than out of Louisville? Data: Sample Flights from Dayton, Ohio and Louisville, Kentucky to 8 destinations Destination Dayton Louisville Chicago-O Hare 319 142 x-bar D x-bar L Diff Grand Rapids, MI. 192 213 318 261.25 56.75 Portland, Ore. 503 317 D ơ L ơ Atlanta 256 387 93.74 82.6 Seattle 339 317 S D S L South Bend, Ind. 379 167 8786.86 6823.07 Miami 268 273 Dallas-Ft. Worth 288 274 Hypotheses: Ho: D L μ ≤ μ Ha: D > L μ μ Test Statistic: 1) Significance Level: Alpha = .05 t-Test: Paired Two Sample for Means Reject Rule: Reject Ho if t > 1.89 Dayton Louisville Mean 318 261.25 Variance 8786.86 6823.07 Observations 8 8 Calculations: x-bar D = 318 Pearson Correlat 0.05 x-bar L = 261.25 Hypothesized Me
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Unformatted text preview: Hypothesized Me df = 7 df 7 t = 1.32 t Stat 1.3206 p-value = 0.114 P(T<=t) one-tail 0.11 t Critical one-tail 1.89 Conclusion: Do Not Reject Ho P(T<=t) two-tail 0.23 t Critical two-tail 2.36 Business Answer: These samples do not provide sufficent evidence to be able to conclude that the average cost to fly out of Dayton, Ohio is more than the cost to fly out of Louisville, Kentucky. B) Business Question: Is there a difference in the average cost of flying out of Dayton compared to Louisville? Reject Rule: Reject Ho if t > 2.36 Calculations: p-value = 0.23 t = (x-bar1 - x-bar2) / (s1 2 /8 + s2 2 /8)^.5 and if Ho is true: and D = L this is t distributed with df we can calculate μ μ...
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