# HWK 9 - 0.08 0.01 ( 1/15 *((.64^2)/16)^2)...

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Homework #10 Problem #17 Business Issue The financial consulting servies for Merril Lynch Business Question Does the company with more years of experience have a higher population mean service rating Data Consultant A Consultant B N1 = 16 N1 = 10 x-bar = 6.82 x-bar = 6.25 S1 = .64 S1 = .75 Exp Yrs = 10 Exp Yrs = 1 Analysis Hypotheses Ho: a b μ ≤ μ Ha: a > b μ μ Test Statistic Sig Level Alpha = .05 Reject Rule Reject if t >TINV ( .1,18.6045) 1.73 Calculations x-bar A = 6.82 x-bar B = 6.25 df = (s1^2/n1+ s2^2/n2)^2 / (1/n1 -1 *(s1^2/n1)^2) + (1/n2-1( s2^2/n1)^2) ((.64^2)/16)+((.75^2)/10)
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Unformatted text preview: 0.08 0.01 ( 1/15 *((.64^2)/16)^2) (1/10*((.75^2)/10)^2 18.6 t = (x-bar1 - x-bar2) / (s12/12 + s22/12)^.5 (6.82-6.25)/(((.64^2)/16)+((.75^2)/10)^.5) 2.17 p-value = TDIST( 2.169, 18.6045, 1) 0.02 Conclusion Reject Ho Business Answer According to the Samples taking for the two financial consultants there is sufficent evidence to conclude that consultant A has a higher population mean for service rating. t = (x-bar1 - x-bar2) / (s1 2 /12 + s2 2 /12)^.5 and if Ho true and μ 1= μ 2, t distributed with df we can calc....
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## This note was uploaded on 07/17/2011 for the course STATS 211 taught by Professor Dunne during the Spring '07 term at University of Dayton.

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