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Post-lab 4 Qualitative-problems-1

Post-lab 4 Qualitative-problems-1 - wetsel(zpw67 Post-lab 4...

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wetsel (zpw67) – Post-lab 4 Qualitative – lyon – (51900) 1 This print-out should have 21 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points A variety of ions including Na + , K + , NH 4 + , Pb 2+ , Fe 2+ , NO 3 - , Cl - , Br - , S 2 - , and CO 3 2 - are mixed in a beaker of water. If you analyzed the precipitates, which substances would you expect to find? 1. NaNO 3 and K 2 S 2. PbS and FeCO 3 3. FeCO 3 and KNO 3 4. FeCl 2 and KCl 5. FeS and Na 2 CO 3 6. PbCO 3 and NaCl 7. NaBr and Pb(NO 3 ) 2 002(part1of2)10.0points Identify the correct net ionic equation for the formation of copper (II) phosphate precipi- tate from solution. 1. 2 Cu 2+ (aq) + PO 3 - 4 (aq) Cu 2 PO 4 (s) 2. 3 Co 2+ (aq) + 2 PO 3 - 4 (aq) Co 3 (PO 4 ) 2 (s) 3. 2 Co 2+ (aq) + PO 3 - 4 (aq) Co 2 PO 4 (s) 4. 3 Cu 2+ (aq) + 2 PO 3 - 4 (aq) Cu 3 (PO 4 ) 2 (s) 5. Cu + (aq) + PO - 4 (aq) CuPO 4 (s) 6. 2 Cu 2+ (aq) + P3 - (aq) Cu 3 P 2 (s) 7. Cu 2+ (aq) + PO 3 - 4 (aq) Cu 3 (PO 4 ) 2 (s) 003(part2of2)10.0points Identify the correct net ionic equation for the formation of tin (IV) sulfide precipitate from solution. 1. Ti 4+ (aq) + 2 S 2 - (aq) TiS 2 (s) 2. 2 Ti 2+ (aq) + S 2 - (aq) TiS (s) 3. Sn 4+ (aq) + 2 S 2 - (aq) SnS 2 (s) 4. 4 Sn 2+ (aq) + 4 S 2 - (aq) 4 SnS (s) 5. 4 Sn 4+ (aq) + 2 S 2 - (aq) 2 Sn 2 S (s) 004(part1of4)10.0points In each of the following four situations, imagine that you have two unlabeled beakers in front of you which contain the two solu- tions listed. For each set of solutions, select a reagent from the list provided that could be added to both beakers in order to make a dis- tinction between the two solutions. In each case identify the precipitate that is formed. Situation 1) BaCl 2 and Ba(ClO 3 ) 2 1. Add NaCl to form barium chloride 2. Add AgNO 3 to form silver chloride 3. Add K 2 CrO 4 to form barium chromate 4. Add K 2 CrO 4 to form potassium chlorate 5. Add Na 3 PO 4 to form barium phosphate 6. Add H 2 SO 4 to form barium sulfate 7. Add AgNO 3 to form barium nitrate 8. Add NaCl to form sodium chloride 005(part2of4)10.0points
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