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Unformatted text preview: C that makes the equation true. (Sea level is 3,963 miles from the center of the Earth.) 100= c39632 100*3963 2 =C C= 1,570,536,900 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level). W=1570536900*3936 28252802 W= 100.04 ii. the top of Mount McKinley (20,320 feet above sea level). W=1570536900* + 3963 2032052802 W=15,735,883.06 2. The equation gives the distance, D , in miles that a person can see to the horizon from a height, h , in feet. a. Solve this equation for h . H= . D1 22 b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. h=14288 Yes you could see it because 89 is less than D=1.2 14255 = 143.27 miles 143.27 miles MAT/117 MAT/117...
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This note was uploaded on 07/18/2011 for the course MAT 117 taught by Professor Alkofahi during the Spring '09 term at University of Phoenix.
 Spring '09
 ALKOFAHI
 Algebra, Radicals, Equations

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