PM homework _2 solutions

PM homework _2 solutions - PSP CHEMISTRY Name Homework...

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Unformatted text preview: PSP CHEMISTRY Name: \/ Homework Assngnment PM#2 uh- O, .30“ bk 1 : , 0 3 ,. o ‘ , Due Thursday June 3 / yaw» {)0 v / m PM why 31,1114 What is the percent by mass of magresium (Mg) in magnesium oxide (MgO)? 1. M3053“? K ,00 r (70, rot/2, S 6") Ham 3 ”1,0 M} 2. In one experiment, the burning of 0.312 g of sulfur produced 0.623 g sulfur dioxide (802) as the sole product of the reaction. In a second experiment 0.842 g of sulfur dioxide was obtained. What mass of sulfur must have been burned in the second experiment? fling aomafi 66 9419” pfflm «fictimflffil 99* 03936 ,rgooz— 50.1%5 0,933 sq,“ cxP‘d‘Mn-l'gl X S . p / meadows?) )95=_s:z/a8.fl):o.q2235 03%1 :00 n a. In one experiment, the reaction of 1.00 g mercuryr (Hg) and an excess of sulfur (S) yielded 1.16 g of a sulfide of mercury as the sole product. In a second experiment. the same sulfide was produced in a eaction of 1.50 g mercury and 1.00 g sulfur. (a) What mass of the sulfide of mercury was produced Q‘ in the second experiment? (13) What mass of which element (mercury or sulfur) remained? ‘thk 70 mm.“ H} Ffam Mflt’r’lMflr# 1 MJ)‘ DO -_-_ 5/192 ‘70 171:) J r [3 f.) Hut-95¢ 1"" (M’mud D {5‘ C0) 1E5 Hm: 86"? .- . 1x113 ”Will... R . . xsew (Tweet? (a) W: WW U923 {3-0 H) X100- 17Li mMflA wapbtlgbfiparflh «LS-‘3 Hg ”1 XWW: 4r???“ ’ ‘ 3 ”Wine” ;q 5 m1 . r i) l , * Mamet) __../—-——-———O 3’ . . Smj [.0035 M12400 ‘3‘ _ . W.” in maria f1” ],oo*C,J-Q=OA%5J mli’w’ M9 (“up I __ Loofisflaod 2,13} {.emfwtrol Then We ”7 W” . nmiw‘. 1 xngfinflpmfl. ' ”TH-H ’ " ‘ ‘ ./ u — r u" '_ r [[29 {P.Hn 4. The followin data were obtained for com unds of iodine I and fluorine (F): If the formula for compound A is IF, what are the formulas for compounds B, C and D? _ COmPoman i4 3 15 I : 0.1de F ‘1’“??? = )F Kw Malt: M 1 am.“ of cm I Fatwa ‘___——-“ at“??? . ;' anon-W 1' . F . : IF wmflmd B 0- zzwxl =fla~r~ffiljf (93%;3 r ( I F 2 F) 53F CMFOWWI B 3 3 am 131' : 0. W913 F COMPOMACQ C: (9.757% KL33: far A (9‘ka P )F 2 If“ can-1mwflvp C 2: I%— 0.3TaHj «is/.33 3 0.79333 1’ . admit? 5-: 15,: a 0.7965" F i - . ~— , .- ‘- O: I F : 1 0i 0: I command 0. 1,034.- . Lo‘wofiy [10% 3 (W735 7F ( Cam/ow F7( 5. The two most common oxides of carbon (C) are carbon monoxide (CO) and carbon dioxide (C02). Another oxide of carbon has 1.106 g of oxygen in a 2.1350 g sample. In what ratio are carbon and oxygen atoms combined in molecules of this third oxide? I ‘ CD Mnknéwn COMFOMIIOQ 1.7379? Sflr‘W-L Carbon monoxide. ( > .flmficfl Rj C . H93 0 A 1.29% area/x B“ 2’? C .-_ 3%.“ ”33 O MHHMDWA COMfJOUW; J}— . I tilt-5W3 C . LIOQJ U lv’j C , I353 0 lg; O 5 law . L109: — 083’“? 0 who Combr‘mcl “H" {'Dfic ‘ 5 Tm ; '5 C ‘ rm ' 3 an5 cm mm m were } C i- D. 35/ij O 3 . .. , _ J: 93%;) o i own) :DJpéS' M5- 3 car 0“ C £3390 0.L&Bk3:20xY95 4‘1"" “my i COU’EOA cit-pm Tram- 3> 0-9“ 0*?3‘" “4° -- 1:2 40 122 59 120 53 39 6. §DSn 1 3 Ar b_J_Te 93? Cu ~0Cd ”Co "(K Arrange the species above in order of increasmg Mad-er at clearer; (a) number of electrons. In Pm’tW‘ s o . 2. ._ . in _ Ware?) 4 fix (a) < ‘52,. (2?) < 5142?) < D" CA? (at) 4 “ 94 (>0) < T: (.52) 5 ‘JS K6 (b) number of neutrons. number of “WV? “18' “" fink" 6' . .. '5'- nl _ L21 [70) < 110d (7%) “BIN (20‘) 4 ”ED/44¢) Aglafic) < 3 Cu 3:) < 542:) 4 "i; 0 mass. 0 55’ . ‘ [L0 11:. U MK ‘ Lt!” 4 C0 ‘1 575% < “Sn 4 Ca? < 7:: 7 . . An isotope with a mass number of 44 has four more neutrons than protons. This is an isotope of what element? it'l' P: number of PrO'iMS 6 “Han 00+ (.0 : n umber oi: Mum/l5 P + (PM W 2‘? H1 =HL1 2’93110 P: 20 mmfiT—B‘C Calcium 10 prO‘fiDflS 8. Iodine has many radioactive isotopes. Iodine—123 (ml) is used for obtaining images of the thyroid gland. Iodine-123 is given to patients in the form of sodium iodide capsules that contain 1231' ions. Determine the number of neutrons, protons, and electrons in a single ”’1' ion. 1:13 — 513 prams (arm New '9" 33) 7o mwmfls J.— 53 pfo‘ivAS $5 I13—11‘3 f 70 neutrons 5-2} enema; . , _, ‘f'__ -- --I charge 50 one—mom: WP ’ 5‘16 9. Americium-24l (24]Am) is a radioactive isotope that is used in smoke detectors. How many neutrons, protons and electrons are there in one atom of americium-241 ‘? 31““ qs‘PrOT‘On S (aha-Sc; nun-1hr) h ‘7? Am ‘iS-tlnc/Voflfi C 5.3M (.25 probns W5; AmK’al abm) P 1%, néwkflns ’2)“ fly : ML, J? 10. There are three naturally occurring isot0pes of magnesium (Mg). Their masses and percent natural abundances are 23.985042 u (78.99%), 24.985837 11 (10.00%). and 25982593 11 (11.01%). Calculate the weighted average atomic mass of magnesium. 1335091 M(O,7f‘i¢]) +— l‘tfifS’t'D/OIOEDO) #— ZSrfils—qBHZ‘gJIOI) M ~l 2t 3! a l “ . l gfis man‘s-a 1» 2mm u. + 2.3“” u H 11. The two naturally occurring isotopes of silver( (Ag) have the following abundances: 107Ag (51.84%) and “Eng (43 16%). The exact mass of10 Ag is 106 905092 11. What 15 the exact mass of mAg? ~90,“ permeate twat. aivtm‘c, mus For F13 -‘ 20?.Yéifil Lt id" X 1- mass or {‘3‘} ‘ Ljy (oqgig) + iOéflC'D—Ocil u(O-515"1) :- 10), 9432 LA 9 0.03“. X 4* s’>‘i‘~(}‘1(, u = {Dietitian 14 —55\,qu¢ —5‘5_‘f e. [A (9-‘t8ILx 3 j‘l_\{q&(, M X: SIR-(“43L ct _ O WY“, 12. Bromine has two naturally occurring isotopes. One of them, bromine- 79 (79Br) has a mass of 78 918336 1.1 and a natural abundance of 50. 69%. What must be the mass and percent natural abundance of the other isotoPe? _ L '2 77.?0Lf (A. Wni 551’,"me 7.? ‘ a .0? ‘2; F? W are. 2 nah/1m“? oceum‘n) Rows of Sr Gaga 0'" 5"“ 59 30M? ; 199-5-o.c?=4‘13i‘ - * 2‘ q €37mm33t u (Mot?) + XfiM‘fS’I) = Pita! UL mm: am (SF 0"“!!! MW}: 49,0091 at + mm: ,1; : 71%: M 410.00% ‘ _ vwvw \ 0.11am >r ' 3:] 700 LL ><: 3619000 :307fl7é5‘ =i5’0fll u. ’ «9‘68: ngr admi Mats .~ 90-6-2 (A 13. What are the percent natural abundances of the two naturally occurring isotopes of boron, 10B (10.012937 u) and “B (11.009305 u)? %M FCI’I‘ £501. 90‘6‘1C am; mac; @ B: 10.91! M Leif— ncot'nrqi abuncflmflcc (ruffle) 0'9 KB 3 X ‘H'xLA {Mk/mi nbwwiame m‘hiv 1%,, ”5: I'X JO.OIl‘i37u(X) + 11,009301‘11 (PX) ~—- rot“ tt % 10.012937x + Itofizoy—”teat/30y)V : 10.8}; (A e -if.00'3?0$' - —H.OO‘:730J 10.0r2‘i37 x -- Il.oe‘i‘3t>f,\.T = -— 0.1% 303' (A -O.‘?%3L§{X : —&.I?E3OS’ u t: x: ~O-i‘ia‘305‘ox : £qu >I003 W320 ”Gianni ...
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