midterm-2-review

# midterm-2-review - Answers to special review exercises for...

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Answers to special review exercises for midterm 2 Michael Lugo November 1, 2010 15.18(a) There are two ways that this can happen - A 2 ,B 5 or A 5 ,B 2. There are 30 possible outcomes, all equally likely. The answer is 2 / 30 = 1 / 15. 15.18(b) A sum of 7 can occur as A 1 ,B 6; A 2 ,B 5; A 3 ,B 4; A 4 ,B 3; A 5 ,B 2. Thus 5 out of the 30 possible equally likely outcomes have sum 7; the answer is 5 / 30 = 1 / 6. 15.18(c) One number is bigger than twice the other if the numbers are A1, with B3, B4, B5 or B6; A2, with B5 or B6; A3, with B1; A4, with B1; A5, with B1 or B2. So there are 10 total outcomes where one number is bigger than twice the other,out of 30; the answer is 10 / 30 = 1 / 3. 15.19(a) This is (39 / 52) × (38 / 51) × (37 / 50) × (13 / 49) 0 . 110. The factors of the product are conditional probabilities. 15.19(b) There are 49 cards left, of which 13 are hearts; the answer is 13 / 49. 15.20 ± 10 3 ²± 1 2 ² 10 = 10 × 9 × 8 3 × 2 × 1 ± 1 2 ² 10 = 120 1024 = 15 128 0 . 117 23.11(a) This description describes the process of ﬁnding the regression line for predict- ing the income of the wife from the income of the husband. The regression line has slope r × SD ( y ) /SD ( x ) = . 33 × 30000 / 40000 0 . 25. 23.11(b)

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midterm-2-review - Answers to special review exercises for...

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