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Unformatted text preview: Stat 20: solutions to homework 1 Michael Lugo September 30, 2010 Chapter 10, # 3 (a) The husband is (72 68) / 2 . 7 = 1 . 48 SD above average. The wife is therefore predicted to be 1 . 48 × . 25 = 0 . 37 SD above average, which is 63+0 . 37 × 2 . 5 = 63 . 92 inches. We’ll round this to 64, since the height of the husband was given in whole inches. (b) The husband is (68 64) / 2 . 7 = 1 . 48 SD below average. So the wife will be 0 . 37 SD below average, which is 63 . 37 × 2 . 5 = 62 . 08 inches. As before, we round to 62. (c) Since the height of the husband is average, the height of the wife is predicted to be average, as well – 63 inches. (d) Since we know nothing about the height of the husband, the height of the wife is predicted to be 63 inches. Chapter 10, # 4 (a) The woman is 2 SD above average, so the man is predicted to be 2 × . 5 = 1 SD above average; thus we predict 12 + 3 = 15 years of education....
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This note was uploaded on 07/21/2011 for the course STAT 20 taught by Professor Staff during the Spring '08 term at Berkeley.
 Spring '08
 Staff
 Statistics, Probability

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