practiceexam12 - City College Chemistry Department...

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1 City College, Chemistry Department Chemistry 10301, sections T and T2, Prof. T. Lazaridis Final exam, Dec 22, 2005 Name (last name first): _____________________________________________ I.D. Number: ______________________________________________________ Workshop leader:__________________________________________________ Note: There are 17 questions in this exam. Fill in your answer in the blank space provided immediately following each question. 1/2 point will be subtracted every time you report a numerical result with an incorrect number of significant figures. A Data Sheet with useful information is at the end. 1. (4) Write the names of the elements below next to their atomic symbols: Ti Titanium Mg Magnesium Al Aluminum Kr Krypton 2. (4) Write the molecular formula next to the names of the following compounds: Magnesium Sulfate MgSO 4 Sodium Carbonate Na 2 CO 3 Barium Hydroxide Ba(OH) 2 Potassium Nitrate KNO 3 3. (8) Balance the following chemical equations: 2 C 6 H 6 + 15 O 2 12 CO 2 + 6 H 2 O 3 CaCl 2 + 2 Na 3 PO 4 Ca 3 (PO 4 ) 2 + 6 NaCl 2 KClO 3 2 KCl + 3 O 2 4 FeO + O 2 2 Fe 2 O 3
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2 4. (8) How many grams of phosphoric acid will form when 30.0 g of P 4 O 10 is mixed with 75.0 g of water? The reaction is P 4 O 10 + 6H 2 O 4H 3 PO 4 Molar masses: P 4 O 10 : 4X30.97 + 10X16.00 = 283.88 g/mol H 2 O : 2X1.008 + 16.00 = 18.02 g/mol H 3 PO 4 : 30.97 + 4X16.00 + 3X1.008 = 97.99 g/mol P 4 O 10 : 30.0 / 283.88 = 0.106 mol H 2 O : 75.0 / 18.02 = 4.16 mol 4.16/0.106 = 39.24 >> 6 therefore P 4 O 10 is limiting 0.106 moles P 4 O 10 will give 4 X 0.106 = 0.424 mol H
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This note was uploaded on 07/21/2011 for the course CHEM 111 taught by Professor Sawyers during the Spring '11 term at Virginia College.

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practiceexam12 - City College Chemistry Department...

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