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Unformatted text preview:  n ﬂips of 2 nd coin heads]= ( 2 3 )( 3 4 ) n / [( 2 3 )( 3 4 ) n + ( 1 3 )( 4 5 ) n ]. 2e. LIM n →∞ [answer to (d)]=0 since ( 4 5 ) n dominates ( 3 4 ) n . 2f. Coin C is more likely than coin B to land heads indeﬁnitely. 2g. Pr [ E ] = Pr [ E ∩ F ] + Pr [ E ∩ F ] → Pr [ E ∩ F ] = Pr [ E ]Pr [ E ∩ F ] = Pr [ E ]Pr [ E ] Pr [ F ] = Pr [ E ](1Pr [ F ]) = Pr [ E ] Pr [ F ] → E,F are independent. Q.E.D. All these from Problem Set #1. 3a. C,Y,0. 3b. U,Y,1. 3c. C,Y,0. 3d. U,Y,0....
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This note was uploaded on 07/22/2011 for the course EECS 370 taught by Professor Lehman during the Spring '10 term at University of Florida.
 Spring '10
 Lehman

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