{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

7328569 - (0,0 x y 40 o We have vo=180ftsec =40o to the...

This preview shows pages 1–2. Sign up to view the full content.

40 o y (0,0) x We have, = vo 180ftsec = θ 40o to the horizontal Velocity in y-dir n : = vy vosinθ Velocity in x-dir n : = vx vocosθ Parametric equations that describe the position of the ball as a function of time After time t, using the equation of motion = + s ut 12at2 for both x and y-dir n : Motion in y- dir n is given by: - = - y yo vosinθt 12gt2 Motion in x- dir n is given by: - =( ) x xo vocosθ t The ball was hit 3 ft off the ground. = yo 3 ft Motion in y- dir n is given by: - = - y 3 vosinθt 12gt2 .................. [1] Motion in x- dir n is given by: =( ) x vocosθ t ................... [2] Duration for which the ball was in the air Let ball was in the air for a time tf Using equation [1] at = y 0 we get: - = - 0 3 vosinθtf 12gtf2 - = - 3 vosinθtf 12gtf2 - . - = 16tf2 115 7tf 3 0

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 2

7328569 - (0,0 x y 40 o We have vo=180ftsec =40o to the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online