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7328569 - (0,0 x y 40 o We have vo=180ftsec =40o to the...

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40 o y (0,0) x We have, = vo 180ftsec = θ 40o to the horizontal Velocity in y-dir n : = vy vosinθ Velocity in x-dir n : = vx vocosθ Parametric equations that describe the position of the ball as a function of time After time t, using the equation of motion = + s ut 12at2 for both x and y-dir n : Motion in y- dir n is given by: - = - y yo vosinθt 12gt2 Motion in x- dir n is given by: - =( ) x xo vocosθ t The ball was hit 3 ft off the ground. = yo 3 ft Motion in y- dir n is given by: - = - y 3 vosinθt 12gt2 .................. [1] Motion in x- dir n is given by: =( ) x vocosθ t ................... [2] Duration for which the ball was in the air Let ball was in the air for a time tf Using equation [1] at = y 0 we get: - = - 0 3 vosinθtf 12gtf2 - = - 3 vosinθtf 12gtf2 - . - = 16tf2 115 7tf 3 0
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7328569 - (0,0 x y 40 o We have vo=180ftsec =40o to the...

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