7331911 - Solution: The induced field is given by the...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Solution: The induced field is given by the general form (Maxwell's equation): E = -∂ ∂ dl Φ t ………….[ ] 1 By symmetry for the conditions given, the integral can be simplified to - * E 2πr And, the total flux = = Φ B dA * = * …………. B Area B πr2 2 * = - ∂ ∂ Et 2πr1 πr22 B t where, r1 is the radial distance, r2 is the magnet radius = . 3 1 cm (a) Radial distance, = . r1 0 9 cm Since, < r1 r2 , then r1 is used both sides, * = - ∂ ∂ Et 2πr1 πr12 B t = - ∂ ∂ Et r12 B t = . + . B 25 65 5 35sin2πft ∂ ∂ = . ( ) B t 5 35 X 30π cos 30πt = . . ( ) Et 0 0092X 5 35 X 30π cos 30πt The amplitude of = . . E1 0 0092X 5 35 X 30π ( )= . / amp E1 2 27 V m (b) Radial distance, = . r1 1 8 cm
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 07/22/2011 for the course ME 3 taught by Professor Prof.ramachandran during the Spring '11 term at Indian Institute of Technology, Kharagpur.

Page1 / 2

7331911 - Solution: The induced field is given by the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online