7336188 - We have, x'=Ax Where, A=413646-5-2-4 Eigenvalues,...

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We have, = x' Ax Where, = - - - A 413646 5 2 4 Eigenvalues, λ of the above matrix A are 1,1,2 The eigenvector, v is calculated by: = - v A λIx = 0 - - - - - - = 4 λ1364 λ6 5 2 4 λx1x2x3 0 v1 can be calculated corresponding to eigenvalue λ =1 with algebraic multiplicity two (i.e.
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This note was uploaded on 07/22/2011 for the course ME 3 taught by Professor Prof.ramachandran during the Spring '11 term at Indian Institute of Technology, Kharagpur.

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7336188 - We have, x'=Ax Where, A=413646-5-2-4 Eigenvalues,...

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