MAT117WK3DQ1 - the square of the starting amount. Then...

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(^2-1)(X-1)-x =(x-1) (x+1) (x-1)-x =(x+1)-x =1 I choose the digit 5. The square is 25. After I subtracted 1, I ended up with 24. When I divided by 4, I ended up with 6. Then subtracting the original number I ended up with 1. So yes, it does work. If you use whichever digit cube and subtract eight. After that, divide with two minus the original digit. Then subtract
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Unformatted text preview: the square of the starting amount. Then subtract two times the starting digit. Was four your solution? (X^3-8)(X-2)-x^2-2x =(x-2) (x^2+2x+4) (x-2)-x^2-2x =(x^2+2x+4)-x^2-2x =4...
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This note was uploaded on 07/23/2011 for the course MATH 117 taught by Professor Rebello during the Winter '09 term at University of Phoenix.

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