Answers to even numbered problems Ch. 5-6 5th ed.

# Answers to even numbered problems Ch. 5-6 5th ed. -...

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Chapters 5 & 6 - 5 th edition Answers to even-numbered problems Chapter 5 5.2 µ = 2.752 σ 2 = 2.752496 σ = 1.6591 5.4 µ = 1.201 σ 2 = 0.96260 σ = .98112 5.6 a) P ( x =12) = .120 b) .113 c) .113 d) .133 e) .876 f) .382 5.8 a)

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Chapters 5 & 6 Answers to even-numbered problems Page 2 b) c) 5.10 P ( x > 9) = .142 P (3 < x < 6) = .508 P ( x = 10) = .1376 P ( x = 13) = .1898 Expected Value = 11.44
Chapters 5 & 6 Answers to even-numbered problems Page 3 5.12 .106 . 0260 5.14 a) 5.4 , 6.12 b) .141 c) .2076 d) .0016 , .00056, 30% produces higher probability (\$ 500k to \$1 million) 5.16 a) .0936 b) .0098 c) .7786 d) .1496 e) .9714 f) .3817 5.18 a) .0407 b) .0608 c) .1523 , .8477 , 15.23% d) .1128 , .6579 5.20 a) .0037 b) .1584 c) .0008 Because this probability is so low, if it actually occurred, the researcher would question the Lambda value as too low for this period. Perhaps the value of Lambda has changed because of an overall increase in pollution. 5.22 a) .3012 b) .0988 c) .4628 The result is likely to happen almost half the time (46.26%). Ship channel and weather conditions are about normal for this period. Safety awareness is about normal for this period. There is no compelling reason to reject the lambda value of 0.6 collisions per 4 months based on an outcome of 0 or 1 collisions per 6 months.

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