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Unformatted text preview: c with respect to q = derivative of c ! c = 0 . 4 2 q + 4 = 0 . 8 q + 4 in which we plug in q = 2 and we get c (2) = 0 . 8 2 + 4 = 1 . 6 + 4 = 5 . 6 As for c q we dont use the derivative at all! ; what we need is c = c (3)c (2) = (0 . 4 3 2 + 4 3 + 5)(0 . 4 2 2 + 5 2 + 5) = = 3 . 6 + 12 + 51 . 6105 = 4 q = 32 = 1 and so c q = 4 1 = 4 36. Proof. (a) rate of change of y with respect to x = derivative of y = y = f ( x ) = (42 x ) =2 (b) relative rate of change= y y =2 42 x (c) plug in x = 3 in the formula in (a): y (3) =2 (its a constant! so anything we plug in will give us2) (d) plug in x = 3 in the formula in (b): y y (3) =2 42 3 =2 46 =22 = 1 (e) just express the result in (d) in percentage form: 1 = 100 100 % = 100%...
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 Spring '08
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 Math, Calculus

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