sol16-4 - SOLUTIONS CHAPTER 16.4 MATH 132 WI00 What I'll do...

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SOLUTIONS CHAPTER 16.4 MATH 132 - WI00 What I’ll do in the following. .. since you are now skilled in computing integrals ... will be just give you the idea (the u , that is) and the result you should get. Mind the fact that you might follow a diFerent method (there’s no mathematics problem that admits only one solution!!), and you might get a diferent looking result - then your job will also be to check your answer :), since the answers should be the same. 6. Take u = e x 2 - 2. Reasons: taking just x 2 is not enough (try it!), so this would be the next step this u combines a constant too - always take the expression that has constants in it for u , since by diFerentiation it will vanish (as opposed to NOT showing up after diFerentiation) Result: 1 2 ln( e x 2 - 2) + C 12. We can use the u -trick here, but with a twist! Since we have x - 5 as the denominator, and we cannot really get rid of it, the one thing we can do to simplify our work is to call it u : u = x - 5 du
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sol16-4 - SOLUTIONS CHAPTER 16.4 MATH 132 WI00 What I'll do...

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