19-Density-Ans

19-Density-Ans - CHEM I LAB DENSITY CONCEPT PROBLEM ANSWERS...

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CHEM I LAB DENSITY CONCEPT PROBLEM ANSWERS 1 milliliter (ml) of a liquid = 1 cm 3 of a liquid at 4 o C Density Solid & Liquid: Density (grams/cm 3 ) = Mass (grams)/ Volume (cm 3 ) Density Solution: Density (grams/cm 3 ) = Mass solute + solvent (grams)/Volume solvent (cm 3 ) Density Geometric Solid: Density (grams/cm 3 ) = Mass (grams)/Geometric volume formula (cm 3 ) Ex: Formula Cylinder Volume = (π) * (r 2 ) * (length) density = mass/(π) * (r 2 ) * (length) length = mass/(D)* (π) * (r 2 ) radius (r) = √ mass/(π)*(length)*(density) 1) A gold ring was weighted on a centi-gram balance and the mass was 24.95 grams. The volume of the ring was determined to be 1.330 cm 3 . What is the density of gold (grams/cm 3 ) ? D = Mass/Volume D = 24.95 grams/1.330 cm 3 = 18.7593 S/F =4 18.76 grams/cm 3 2) Bromine is a liquid at room temperature and has a density of 3.824 grams/ml at 25.0 o C. What volume (mls) will 50.0 grams of bromine occupy ? D = Mass/Volume Volume = Mass/Density = 50.00 grams/3.824grams/cm 3 = 13.0753 S/F =3 13.1 grams/ml 3) If 75.6 mls of hydrochloric acid (HCl) solution has a density of 1.275 grams/milliters, what is the
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This note was uploaded on 07/28/2011 for the course CHM 2045 taught by Professor Eng during the Spring '10 term at UNF.

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19-Density-Ans - CHEM I LAB DENSITY CONCEPT PROBLEM ANSWERS...

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